120 days in 4 months start day 1 with 4 rats every 4 days 4 rats add on so what I did is this.
Day 1= 4 rats day 4=8 day 8 = 12 so on intell u hit 118 days.but the answer to your question is.. there will be 114 rats if the population of rats double every 4 days for 4 months. hope this is correct and helps. :)
Answer:
$27428.57
Step-by-step explanation:
To solve this problem, we can use the formula for compound interest:
P = Po * (1 + r)^(t)
Where P is the final value, Po is the inicial value, r is the rate of interest, t is the time.
With r = 0.06, t = 4 (The rate is for every 15 days, and the time is 2 months, so we have that 2 months = 4 periods of 15 days) and P = Po + 7200, we have:
Po + 7200 = Po * (1 + 0.06)^4
Po + 7200 = Po * 1.2625
Po * 0.2625 = 7200
Po = 7200 / 0.2625 = $27428.57
Answer:
Well where are the options for the graphs?
"In Store A, a book that regularly sells for $24.99 is on sale at 15% off. In Store B the same book regularly sells for $27.99 and is on sale at 25% off. Which store sells the book for the lower sale price?"
"the choises are A Store A; Store A’s sale price is $18.74 and Store B’s sale price is $23.79. B Store A; Store A’s sale price is $18.74 and Store B’s sale price is $20.99. C Store B; Store A’s sale price is $21.24 and Store B’s sale price is $20.99. D Store B; Store A’s sale price is $21.24 and Store B’s sale price is $23.79."
15% of 24.99 is 3.7485.
24.99 - 3.7485 = 21.2415
25% of 27.99 is 6.9975
27.99 - 6.9975 = 20.9925
<u>Store B/ Answer C</u>
It said the sale earned OVER $25 from selling cookies at $3 dollars each so if we let r=revenue , p=price per cookie and c=number of cookies sold:
pc>r and since p=3 and r=25
3c>25 divide both sides by 3
c>25/3
Since cookies are quantized units, they must be integers so:
c>8 1/3
c≥9 or in interval notation
c=[9, +oo)
