Based on the population mean, the mean of the distribution sample means would be 204.6. The standard deviation would be 0.22.
<h3>What are the mean and standard deviation of the distribution?</h3>
The mean of the distribution sample means is the same as the population means which is 204.6.
The standard deviation can be found as:
σₓ = σ / √n
= 3.1 / √197
= 0.22
Find out more on standard deviation at brainly.com/question/12402189.
#SPJ1
An easier way to do this is to make the fractions improper fractions.
3 1/6 can be rewritten as 19/6. 1 4/6 can be rewritten as 10/6. (Multiply the denominator by the number at its side, and add it to the numerator).
2 3/6 is 15/6.
Subtract 10/6 from 19/6.
19/6-10/6=9/6.
9/6 is not 15/6, therefore she did not use 2 3/6 yards of fabric.
Answer:
![n\le 5](https://tex.z-dn.net/?f=n%5Cle%205)
Step-by-step explanation:
Let n be the number of tickets Makaya has to buy.
If the cost of one ticket is $1.5, then the cost of n tickets is $1.5n.
Makayla has $8 to buy tickets at the school fair, thus
![1.5n\le 8\\ \\n\le \dfrac{8}{1.5}\\ \\n\le \dfrac{80}{15}\\ \\n\le \dfrac{16}{3}\\ \\n\le 5\dfrac{2}{3}](https://tex.z-dn.net/?f=1.5n%5Cle%208%5C%5C%20%5C%5Cn%5Cle%20%5Cdfrac%7B8%7D%7B1.5%7D%5C%5C%20%5C%5Cn%5Cle%20%5Cdfrac%7B80%7D%7B15%7D%5C%5C%20%5C%5Cn%5Cle%20%5Cdfrac%7B16%7D%7B3%7D%5C%5C%20%5C%5Cn%5Cle%205%5Cdfrac%7B2%7D%7B3%7D)
The maximum number of tickets Makaya can buy is 5, so
![n\le 5](https://tex.z-dn.net/?f=n%5Cle%205)
Answer:
There is an error in the question.
All angles in an equilateral triange are 60º