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Veseljchak [2.6K]
2 years ago
7

In ΔABC, if AB = 14 and BC = 9, AC may be equal to

Mathematics
2 answers:
Mariulka [41]2 years ago
8 0

Answer:

Answer = 13

Step-by-step explanation:

Pie2 years ago
5 0

Answer:

AC could be any number of these numbers 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22

Step-by-step explanation:

There is a fact in any triangle:

<em>The length of any side of a triangle must be greater than the difference of the lengths of the other two sides and smaller than the sum of the lengths of the other two sides</em>

If the lengths of the three sides of a triangle are a , b and c, then

  • a - b < c < a + b
  • b - c < a < b + c
  • a - c < b < a + c

In Δ ABC:

→ (BC) - (AC) < AB < (BC) + (AC)

→ (AB) - (AC) < BC < (AB) + (AC)

→ (AB) - (BC) < AC < (AB) + (BC)

∵ AB = 14 units

∵ BC = 9 units

- Find the sum and difference of them

∵ AB - BC = 14 - 9

∴ AB - BC = 5

∵ AB + BC = 14 + 9

∴ AB + BC = 23

- That means the length of AC could be any integer greater

    than 5 and smaller than 23

∴ 5 < AC < 23

AC could be any number of these numbers 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22

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agasfer [191]

Answer:

  • E = { (4,1) , (3,2) , (2,3) , (1,4) }
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  • P(F|E)=\frac{1}{4}

Step-by-step explanation:

Let's start writing the sample space for this experiment :

S= { (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) , (4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) , (5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }

Let's also define the event E ⇒

E : '' The sum of the two dice is 5 ''

We can describe the event by listing all the favorables cases from S ⇒

E = { (4,1) , (3,2) , (2,3) , (1,4) }

In order to calculate P(E) we are going to divide all the cases favorables to E over the total cases from S. We can do this because all 36 of these possible outcomes from S are equally likely. ⇒

P(E)=\frac{4}{36}=\frac{1}{9} ⇒

P(E)=\frac{1}{9}

Finally we are going to define the event F ⇒

F : '' The number of the first die is exactly 1 more than the number on the second die ''

⇒

F = { (2,1) , (3,2) , (4,3) , (5,4) , (6,5) }

Now given two events A and B ⇒

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We need to find P(F|E) therefore we can apply the conditional probability equation :

P(F|E)=\frac{P(F,E)}{P(E)}   (I)

We calculate P(E)=\frac{1}{9} at the beginning of the question. We only need P(F,E).

Looking at the sets E and F we find that (3,2) is the unique result which is in both sets. Therefore is 1 result over the 36 possible results. ⇒

P(F,E)=\frac{1}{36}

Replacing both probabilities calculated in (I) :

P(F|E)=\frac{P(F,E)}{P(E)}=\frac{\frac{1}{36}}{\frac{1}{9}}=\frac{1}{4}=0.25

We find out that P(F|E)=\frac{1}{4}=0.25

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Answer:

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Step-by-step explanation:

77=4x+57

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Answer:

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