A. First move all to the left side of the equation(Normal form)
x^3 - 49x= 0
B. Factor out an x, which is the GCF (Factored form)
x(x^2 - 49) = 0
C. Find solutions by making each x piece equal to 0. The first part is just x=0 and the second part is just factoring the difference of squares and then solving.
x=0, x^2 - 49 =0
x=0, x + 7 = 0, x - 7 = 0
Therefore, the answers for Part C are:
x = 0, x = -7, x = 7
Answer:
Nope
Step-by-step explanation:
y = 6x - 2
(1, 2)
2 = 6(1) - 2
2 = 6 - 2
2 = 4
(1, 2) isn’t on the line
Answer:
Hey it’s 283
Step-by-step explanation:
Since the equation is A= 1/2 times base times height, I did the base as 8 and the height as 5.
The smallest integer is 1 and middle integer is 2 and largest integer is 3
<h3><u>Solution:</u></h3>
Given that , three times the largest increased by two is equal to five times the smallest increased by three times the middle integer.
We have to find the three consecutive integers
So, let the smallest integer be n, then the next two consecutive middle and largest integers will be n + 1, n + 2 respectively
Then, by the given statement,
Three times the largest increased by two is equal to five times the smallest increased by three times the middle integer.

Thus the smallest integer = n = 1
Middle integer = n + 1 = 1 + 1 = 2
Largest integer = n + 2 = 1 + 2 = 3