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Kobotan [32]
4 years ago
7

A toy has various shaped objects that a child can push through matching holes. The area of the sq. Hole is 8 sq cm. The volume o

f a cube shaped block is 64 cubic cm. Will the block fit in the square hole?
Mathematics
1 answer:
sveta [45]4 years ago
6 0

Answer:

  No

Step-by-step explanation:

The volume of a cube is the cube of the edge length, so the edge length of the cube-shaped block is ...

  edge length = ∛(64 cm³) = 4 cm

Then the smallest cross-section will be a square of edge length 4 cm, so will have an area of (4 cm)² = 16 cm².

The 16 cm² shape will not fit through an 8 cm² hole.

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Who would you go about this.
Nostrana [21]
A. First move all to the left side of the equation(Normal form)

x^3 - 49x= 0

B. Factor out an x, which is the GCF (Factored form)

x(x^2 - 49) = 0

C. Find solutions by making each x piece equal to 0. The first part is just x=0 and the second part is just factoring the difference of squares and then solving.

x=0, x^2 - 49 =0

x=0, x + 7 = 0, x - 7 = 0

Therefore, the answers for Part C are:
x = 0, x = -7, x = 7
6 0
3 years ago
Please please help thank you so much
malfutka [58]
Answer:

Nope

Step-by-step explanation:

y = 6x - 2

(1, 2)

2 = 6(1) - 2

2 = 6 - 2

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4 0
3 years ago
Helps me pls what is 283x2492÷8(89)=2838(82x) what is x
Andrei [34K]

Answer:

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Step-by-step explanation:

3 0
4 years ago
The area of a triangle is 20 square feet.
sdas [7]
Since the equation is A= 1/2 times base times height, I did the base as 8 and the height as 5.
8 0
3 years ago
Find the three consecutive integers such that three times the largest increased by two is equal to five times the smallest incre
n200080 [17]

The smallest integer is 1 and middle integer is 2 and largest integer is 3

<h3><u>Solution:</u></h3>

Given that , three times the largest increased by two is equal to five times the smallest increased by three times the middle integer.

We have to find the three consecutive integers

So, let the smallest integer be n, then the next two consecutive middle and largest integers will be n + 1, n + 2 respectively

Then, by the given statement,  

Three times the largest increased by two is equal to five times the smallest increased by three times the middle integer.

\begin{array}{l}{3 \times (n+2)+2=5 \times n+3 \times (n+1)} \\\\ {3 n+6+2=5 n+3 n+3} \\\\ {8=5 n+3} \\\\ {5 n=8-3} \\\\ {n=1}\end{array}

Thus the smallest integer = n = 1

Middle integer = n + 1 = 1 + 1 = 2

Largest integer = n + 2 = 1 + 2 = 3

6 0
3 years ago
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