Find the area of △ABC with side lengths b = 6 and c = 17, and included angle A = 135∘. Round your answer to the nearest tenth

Mathematics

1 answer:

Cloud [144]3 years ago

4 0

Answer:

Area = 36.1 sq. units

Step-by-step explanation:

We will use the "included angle area" formula for a triangle to solve this problem.

The formula is:

$A=\frac{1}{2}abSinC$

Where

a and b are the two sides given

C is the angle given BETWEEN the two sides

From the problem, we can write:

the two sides are 6 & 17, so that will be "a" and "b" of the formula

the included angle is 135, so that will be "C" of the formula

Substituting, we find the answer:

$A=\frac{1}{2}abSinC\\A=\frac{1}{2}(6)(17)Sin(135)\\A=36.06$

Rounded to 1 decimal place,

Area = 36.1 sq. units

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