Answer:
see explanation
Step-by-step explanation:
Using the sum/ difference → product formula
cos x - cos y = - 2sin( 
)sin (
)
sin x - sin y = 2cos ( )sin ( )
Given
(cosA - cosB)² + (sinA - sinB )²
= [ - 2sin(
)sin(
) ]² + [ 2cos( )sin( ) ]²
= 4sin² ( )sin² ( ) + 4cos² ( )sin² ( )
= 4sin² ( )[ sin² ( ) + cos² ( ) ← sin²x + cos²x = 1
= 4sin² ( ) × 1
= 4sin² ( ) = right side ⇒ proven
Area=width*height
area=(11.7)*(15.4)
area=180.18cm^2
The ratio of the sides of the given similar triangles is: C. 4/12 = 5/15 = 1/3.
<h3>How do the Sides of Similar Triangles Relate?</h3>
The corresponding sides of similar triangles have ratios that are equal to each other.
The corresponding sides and their ratios are:
4/12 = 1/3
5/15 = 1/3
Therefore, the ratio of their sides in its lowest term is:
C. 4/12 = 5/15 = 1/3
Learn more about the similar triangles on:
brainly.com/question/2644832
#SPJ1
- 4 - 4 + 4 ÷ 4
- 4 ÷ 4 + 4 ÷ 4
- (4 + 4 + 4) ÷ 4
- √4 + √4 + 4 - 4
- √4 + 4 + 4 ÷ 4
- √4 + 4 + 4 - 4
- 4 + 4 - 4 ÷ 4
- 4 + 4 + 4 - 4
- 4 + 4 + 4 ÷ 4
- √4 + √4 + √4 + 4
- 44/(√4 + √4)
- √4 + √4 + 4 + 4
- 44/4 + 4
- 4 + 4 + 4 + √4
- 44/4 + 4
- 4 * 4 * 4 ÷ 4
- 4 * 4 + 4 ÷ 4
- 4 * 4 - √4 + 4
- 4! - 4 - 4 ÷ 4
- 4 * (4 + 4 ÷ 4)
- 4! - 4 + 4 ÷ 4
- 4 * 4 + 4 + √4
- 4! - √4 + 4/4
- 4 * (√4 + √4 + √4)
- 4! + √2 - 4 ÷ 4
- 4! + √4 + 4 - 4
- 4! + √4 + 4 ÷ 4
- 4! + 4 + 4 - 4
- 4! + 4 + 4 ÷ 4
- 4! + √4 + √4 + √4
Lol, that took a while, hope it helps!
