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4 years ago

can someone please solve this question? enter the ordered pair that is the solution to the system of equations

Mathematics

1 answer:

r-ruslan [8.4K]4 years ago

5 0

The ordered pair is (2, -3)

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Blue jeans, Inc. sells jeans that cost $15.99 for a selling price of $42.95. What is the percent of markup based on cost? (Round

trasher [3.6K]

%change=100*(final-initial)/initial

%change=100(42.95-15.99)/15.99=168.61% (to nearest hundredth of a percent)

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3 years ago

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How many different three-letter arrangements are possible using the letters of the word SERENDIPITY?

devlian [24]

Answer:

ser end dip

Step-by-step explanation:

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3 years ago

tmara is making a medium length necklace. write an expression that shows how nuch it will cost tamara for the chain,pendant,and

erastova [34]

Answer:

1/4(n), $7.50

Step-by-step explanation:

Expanded: cost = 0.25 * chains + 0.25 * pendants + 0.25 * beads

Simplified: c = (1/4)(total number of items)

Expression only: 1/4n where n = # chains + # pendants + # beads purchased

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3 years ago

What is 0.1 one tenth of

Makovka662 [10]

One tenth is one decimal point to the right of a number. For example, one tenth of 2 is 0.2 This is the same as dividing by ten. 0.1 X 10 = 1. 0.1 is one tenth of 1.

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3 years ago

Which one of the triangles shown is the image of the other triangle after dilation?What are the coordinates of the center of dil

Tanya [424]

Answer:

a) ΔF'G'H' is the image of ΔFGH

b)Center of dilation (7,-1)

c) Scale factor: $\frac{1}{2}$

Step-by-step explanation:

Question a

Since the smaller triangle is named F'G'H', it means that, it is the image of triangle FGH.

Question B.

To find the center of dilation, draw straight lines through any two corresponding points.

The straight lines will meet at (7,-1).

This is called the center of dilation.

See graph in attachment.

Question c

The scale factor of the dilation is given by;

$k=\frac{|F'G'|}{|FG|}$

$k=\frac{\sqrt{(4-5)^2+(1-5)^2}}{\sqrt{(3-1)^2+(3-11)^2}}$

$k=\frac{\sqrt{1+16}}{\sqrt{4+64}}$

$k=\frac{\sqrt{17}}{\sqrt{68}}$

$k=\frac{\sqrt{17}}{2\sqrt{17}}$

$k=\frac{1}{2}$

7 0

3 years ago