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Ilya [14]
3 years ago
15

Help plss will give brainliest

Mathematics
1 answer:
worty [1.4K]3 years ago
4 0

Answer:

f(3) = 4(3)-2 = 12-2 = 10

Step-by-step explanation:

By comparing f(3) and f(x), you can see that it is basically replacing the x in the equation with the value of 3.

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How would tell someone how to write 10 power to -12 as a fraction?
Alisiya [41]
You would write it as (1/10^12)

any negative exponent does the same thing

ex: x^-1 turns into (1/x^1)
7 0
3 years ago
Which of the following is true about the expression 5 x 1/4
borishaifa [10]

Answer:

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Elimination Method<br> 2x-4y=12 -x+2y=-6
Readme [11.4K]

Answer:

The given system has INFINITE NUMBER OF SOLUTIONS.

Step-by-step explanation:

Here, the given system of equation is given as:

2 x - 4 y = 12   ...  (1)

- x + 2 y = -6   ......  (2)

Now, to use the ELIMINATION METHOD we either need to cancel out x coefficients or the y coefficient.

Now, to cancel out the x- coefficient in both the equations:

Multiply equation (2) with 2 and add with (1), we get:

2 x  - 2x + 4 y - 4 y = 12 - 12  

or, 0 = 0

Hence, the given system has INFINITE NUMBER OF SOLUTIONS.

5 0
3 years ago
Find the value of x <br><br> Look at the picture^^<br><br> Answer with work please I need help???
dedylja [7]

In right angled triangle

Hypotenuse ² = perpendicular² + base²

  • Base = 22

  • Perpendicular = 27

  • Hypotenuse = x

\implies \:  {x}^{2}  =  {27}^{2}  +  {22}^{2}

Square of 27 and 22 are 729 and 484 respectively.

\implies \: x = 729 + 484

\implies \: x {}^{2}  = 1,213

\implies \: x = 34.82 \: (approx)

3 0
3 years ago
If the ratio of areas of two similar polygons is 25:49, what is the ratio of the corresponding side lengths
mihalych1998 [28]
\bf \qquad \qquad \textit{ratio relations}&#10;\\\\&#10;\begin{array}{ccccllll}&#10;&Sides&Area&Volume\\&#10;&-----&-----&-----\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}&#10;\end{array} \\\\&#10;-----------------------------\\\\

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\&#10;-------------------------------\\\\&#10;\stackrel{\textit{ratio of sides}}{\cfrac{s}{s}}=\stackrel{\textit{ratio of the areas}}{\cfrac{\sqrt{s^2}}{\sqrt{s^2}}}\implies \cfrac{s}{s}=\cfrac{\sqrt{25}}{\sqrt{49}}\implies \cfrac{s}{s}=\cfrac{5}{7}
6 0
3 years ago
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