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3 years ago

True or false: the value of theta represents the distance from a point to the origin when plotting a point in polar coordinates

2 answers:

6 0

False. The value of theta is the angle measured counterclockwise that the vector makes with respect to the positive x-axis.

sweet [91]3 years ago

6 0

Answer:

False

Step-by-step explanation:

In polar coordinates, a point on a plane is represented by P = (r, theta), where r is the radial coordinate and represents the distance from the point to the origin, and theta is the counterclockwise angle formed between the positive x-axis and the segment formed between P and the origin.

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In ANOP, NP is extended through point P to point Q, mZPNO = (x + 14),

Angelina_Jolie [31]

Answer:

Step-by-step explanation:

m∠OPQ = 23°

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3 years ago

Find the least common denominator for these fractions.

Elenna [48]

Answer:

Step-by-step explanation:

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2 years ago

Implicit diffrention problems I am really stuck on

AysviL [449]

Answer:

$\frac{dy}{dx} =\frac{4x^3+3x^2y-5y^2}{10xy-3y^2-x^3}$

Step-by-step explanation:

solving for dy/dx

multiply the equation out to remove parentheses

$x^4 + x^3y = 5xy^2 -y^3$

now differentiating in terms of x ( $\frac{dy}{dx}$ )

$4x^3 +3x^2y + x^3(\frac{dy}{dx} ) = 5y^2 + 10xy(\frac{dy}{dx} )-3y^2(\frac{dy}{dx} )$

isolating dy/dx to one side

$4x^3 +3x^2y - 5y^2= 10xy(\frac{dy}{dx} )-3y^2(\frac{dy}{dx} )-x^3(\frac{dy}{dx} )$

$4x^3 +3x^2y - 5y^2= \frac{dy}{dx}(10xy-3y^2-x^3)$

$\frac{dy}{dx} =\frac{4x^3+3x^2y-5y^2}{10xy-3y^2-x^3}$

5 0

3 years ago

If a/\2+1/a/\2=11, then a+1/a=?

Nadya [2.5K]

Answer:

$\pm \sqrt{13}$

Step-by-step explanation:

$\bigg(a + \frac{1}{a} \bigg)^{2} = {a}^{2} + \frac{1}{ {a}^{2} } + 2 \times a \times \frac{1}{a} \\ \\ \bigg(a + \frac{1}{a} \bigg)^{2} = 11 + 2 \\ \\ \bigg(a + \frac{1}{a} \bigg)^{2} = 13 \\ \\ \bigg(a + \frac{1}{a} \bigg) = \pm \sqrt{13}$

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3 years ago

Is the relation a function?

Margaret [11]

No; a domain value has two range values.

x = -2 then y = 1 and 2

they would form a vertical line, which tells us that it's not a function

8 0

3 years ago