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cupoosta [38]
3 years ago
9

Write a decimal equation that has a product of 3.15

Mathematics
1 answer:
astraxan [27]3 years ago
4 0
 if you just multiply 12.6  by 0.25 = 3.15 
12.6× 0.25 
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The sum of 5 consecutive odd integers is 2,555. What is the sum of the first, third, and last integer?
Lilit [14]

Answer:

The sum of the first, third, and last integer is 1533.

Step-by-step explanation:

<u><em>Step 1: You need to create a equation first:</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

<u><em>How did I make the equation?</em></u>

If n is odd number, n + 2 must be the consecutive odd number

5 , 5 + 2 , 5 + 4 , 5 + 6 , 5 + 8

5, 7, 9, 11, 13  ALL CONSECUTIVE ODD NUMBERS

<u><em>Step 2: Simplifying the equation</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

5n + 20 = 2555

<u><em>Step 3: Solving the equation, with explanation</em></u>

5n + 20 = 2555       Subtract 20 on both sides

        5n = 2535        Isolate the variable by dividing 5 on both sides

          n = 507

<u><em></em></u>

<u><em>Step 4: Plug in the value</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8

507,  507 + 2 , 507 + 4 , 507 + 6 , 507 + 8

507, 509, 511, 513, 515

<u><em>Step 5:  Solve the sum of the first, third, and last integer</em></u>

507 + 511 + 515 = 1533

<u><em>Step 6: THE ANSWER</em></u>

1533

<h3><u><em>Hope this helps!!! </em></u></h3><h3><u><em>Please mark this as brainliest!!! </em></u></h3><h3><u><em>Thank You!!! </em></u></h3><h3><u><em>:)</em></u></h3>
8 0
3 years ago
NAME THE LARGEST ANGLE <br><br> NAME THE SMALLEST ANGLE
Natasha2012 [34]

Answer:

largest: cu smallest: rc

5 0
2 years ago
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In a certain city, the daily consumption of water (in millions of liters) follows approximately a gamma distribution with α = 2
Ne4ueva [31]

Answer:

The probability that on any given day the water supply is inadequate 0.1991

Step-by-step explanation:

Given

α = 2 and β = 3

As per Gamma distribution Function

P(X>9)= 1-P(X\leq 9)\\

Expanding the function and putting the given values, we get -

[tex]1 - \int\limits^9_0 {f(x;2,3)} \, dx \\1- \int\limits^0_0 {\frac{1}{9}xe^{\frac{-x}{3} } \, dx\\\\= 1- \frac{1}{9} [x(-3e^{\frac{-x}{3}}) -\int\limits {(-3e^{\frac{-x}{3}})} \, dx]^9_0= 1- 1/9 [x(-3e^{\frac{-x}{3}}) -9e^{\frac{-x}{3}})} \, dx]^9_0\\1-((\frac{-1}{3} *9*e^({\frac{-9}{3}})- e^(\frac{-9}{3}))- ((\frac{-1}{3} *0*e^(\frac{-9}{3})-e^{\frac{-0}{3}})\\1-((-3e^{\frac{-9}{3} }-e^{\frac{-9}{3}}-(0-1))\\1-(1-4e^{-3})\\1-(1-0.1991)\\1-0.8009\\0.1991

The probability that on any given day the water supply is inadequate 0.1991

5 0
3 years ago
Find the critical value tc for the confidence level cequals 0.95 and sample size nequals 19.
Alex_Xolod [135]

The critical values are fixed values which can be obtained from the standard t crit  tables. We can find the critical value tc when the degrees of freedom and confidence level are given. The degrees of freedom is simply:

Degrees of Freedom = Number of samples – 1

Degrees of Freedom = 19 – 1

Degrees of Freedom = 18

From the t critical tables, the tc corresponding to Degrees of Freedom equal to 18 and Confidence level equal to 95% is as follows:

tc = 2.101

Therefore this means that any t value beyond 2.101, we already reject the null hypothesis.

8 0
3 years ago
A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the
Alex17521 [72]

The equation is that of a parabola, meaning that the maximum (or sometimes minimum) is 1/2 the sum of the solutions found using the quadratic equation.

y = 0 for the 2 solutions to {-b +/- sqrt[b2 - 4ac]} / 2a, where a = -3, b = 152 and c = -1150 from the equation for y. Plug a, b and c into the quadratic formula to get x = 9.2571 and x = 41.4095 as the 2 solutions.

9.2571 + 41.4095 = 50.6666... and the midpoint is 25.3333...

When x = 25.3333..., y = 775.33333.....

To the nearest cent, x=25.33 results in a profit of 775.33.

When x=25.25, Y = 775.31

When x=25.4, Y = 775.32

These are both less than 775.33 when x = 25.33.

3 0
3 years ago
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