F(0)=-(0+2)²+2 = -1*(2)² + 2 = -4 + 2 = -2 y =-2
element of the set x = 0 attribute to an element of a set of y ( calculated y = -2 )
f(1)=-(1+2)²+2 = -1*(3)² + 2 = -9 + 2 = -7 y = -7
<span>element of the set x = 1 attribute to an element of a set of y ( calculated y = -7 )
</span>f(2)=-(2+2)²+2 = -1*(4)² + 2 = -16 + 2 = -14 y = -14
<span>element of the set x = 2 attribute to an element of a set of y ( calculated y = -14 )
</span>f(3)=-(3+2)²+2 = -1*(5)² + 2 = -25 + 2 = -23 y = -23
<span>element of the set x = 3 attribute to an element of a set of y ( calculated y = -23 )
</span>f(4)=-(4+2)²+2 = -1*(6)² + 2 = -36 + 2 = -34 y = -34
<span>element of the set x = 4 attribute to an element of a set of y ( calculated y = -34 )</span>
Answer:
The number of liters for container R = x = 0.5 liters
The number of liters for container S = y = 1.5 liters.
Step-by-step explanation:
Let the number of liters of container R = x
Let the number of liters of container S = y
We are told in the question : that
Container R holds a solution that is 20% alcohol
= 20% × x = 0.20x
Container S holds a solution that is 60% alcohol.
= 60% × y = 0.60y
How many liters of solution from each container should be used to create 2 liters of solution that is 50% alcohol?
Hence;
x + y = 2 ....... Equation 1
x = 2 - y
0.20x + 0.60y = 2 × 50%
0.20x + 0.60y = 1........ Equation 2
Substitute
2-y for x in Equation 3
0.20(2 - y) + 0.60y = 1
0.40 - 0.20y + 0.60y = 1
Collect like terms
0.40y = 1 - 0.40
0.40y = 0.60
y = 0.60/0.40
y = 1.5 liters
Note that :
x = 2 - y
x = 2 - 1.5
x = 0.5 liters
Therefore,
the number of liters for container R = x = 0.5 liters
the number of liters for container S = y = 1.5 liters.
For this you divide the total spent by the total number of pizzas...
16.50/ 3 = $5.50 per pizza.
Answer:
It’s the second one
Step-by-step explanation:
Even # --------- if it ends with 0, # of ways = 6*5*4 = 120 if not, 3 ways for ending digit, 5 ways for 1st digit, 5*4 for middle digits = 300
so total ways = 420
odd # --------- 4 ways of ending digit, 5 ways for 1st digit, 5*4 for middle digits = 400 ways
< 4000: ---------- 3 ways for starting digit, 6*5*4 ways for remaining digits = 360 ways
> 3000 & < 4000 ------------------------ 1 way for starting digit , 6*5*4 for remaining digits = 120 ways
