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Olegator [25]
3 years ago
8

HELP ASAP!!!

Mathematics
2 answers:
romanna [79]3 years ago
4 0
I hope this helps you

kifflom [539]3 years ago
3 0
C is the answer to your question
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Anyone want to help me with my math assignments ill post another question with the assignments on it
arlik [135]

whats the question?

787878787878

7 0
3 years ago
Conrad had $110 to spend on 9 cheese pizzas for a party. After buying them, he had $8.75 left. How much did each pizza cost? Sho
Igoryamba
Subtract 110 and 8.75 and you get 101.25 then divide that by 9 and you get 11.25

3 0
3 years ago
Find domain of y=rad20-6x
Evgesh-ka [11]
Domain, on an "even root" context, means, an even root cannot have a negative radicand, since  say for example \bf \sqrt{-25}\ne -5\qquad why?\implies (-5)(-5)=25

so... you end up with an "imaginary value"

so... for the case of 20-6x
"x", the domain, or INPUT
can afford to have any value, so long it doesn't make the radicand negative

to check for that, let us make the expression to 0, and see what is "x" then

\bf 20-6x=0\implies 20=6x\implies \cfrac{20}{6}=x\implies \cfrac{10}{3}=x

now, if "x" is 10/3, let's see \bf \sqrt{20-6\left( \frac{10}{3} \right)}\implies \sqrt{20-20}\implies \sqrt{0}\implies 0

now, 0 is not negative, so the radicand is golden

BUT, if "x" has a value higher than 10/3, the radicand turns negative
for example  \bf x=\frac{11}{3}
\\\\\\

\sqrt{20-6\left( \frac{11}{3} \right)}\implies \sqrt{20-22}\implies \sqrt{-2}

so.. that's not a good value for "x"

thus, the domain, or values "x" can safely take on, are all real numbers from 10/3 onwards, or to infinity if you wish
5 0
4 years ago
Based on this data, what is a reasonable estimate of the probability that it is sunny tomorrow?
GalinKa [24]
It would be 3:12 so about 25%
3 0
3 years ago
It takes Sam 3 hours to rake the front lawn while his brother, Dave, can rake the lawn in 5 hours. How long will it take them to
OleMash [197]

Answer:

3 hours + 5hours = 8 hours ÷ 2 =

4 hours is your answer.

Step-by-step explanation:

If you have 2 people working and need to know how long it would take them to finish a job. Working together on the same job, you add each of their total hours to do the job alone,, 5 + 3 = 8, then divide the 8 by 2 people

equals 4 hours for 2 people on 1 job.

4 0
3 years ago
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