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Romashka [77]
3 years ago
8

What does 264÷58 equal to​

Mathematics
2 answers:
aalyn [17]3 years ago
5 0

Answer:

4.55

Step-by-step explanation:

264÷58= 4.55

Rudik [331]3 years ago
4 0
4.55 because u just divide them together do all the work and thats what u get
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If you launch the cannonball from the ground instead (hi=0), what does that change in the original equation?
ikadub [295]

Answer:

  the value of hi changes from 58 to 0:

  h(t) = -4.9t^2 +19.8t

Step-by-step explanation:

If the initial height changes, then the term in the equation that represents that height will change. The initial height term is hi, so it changes from 58 to 0.

  h(t)=-4.9t^2+19.8t+0\\\\\boxed{h(t)=-4.9t^2+19.8t}

7 0
2 years ago
Please help me i would appreciate it greatly
Lera25 [3.4K]

Answer:

I would put B

Sorry if it's wrong I would have to know what the test is about to answer this

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Help pls !! how would I write this equation
aev [14]

2x = Twice your age

200 = Two hundred less

> -1 = more than negative


With the information given, your equation would be:

200-2x>-1

7 0
3 years ago
How do you simplify 16m^2/24m^7
denpristay [2]

Answer: 2/3m^5

Step-by-step explanation: 1st Reduce the expression by cancelling the common factors.

6 0
3 years ago
What is the sum of the prime factors of 2014
goblinko [34]

The sum of prime factors of 2014 is 74

<h3><u>Solution:</u></h3>

Given that to find sum of prime factors of 2014

Let us first find the prime factors of 2014

A prime number is a whole number greater than 1 whose only factors are 1 and itself

"Prime Factorization" is finding which prime numbers multiply together to make the original number.

<em><u>Prime factors of 2014:</u></em>

The Prime Factorization is:

2014 = 2 \times 19 \times 53

Thus the prime factors of 2014 are 2, 19, 53

<em><u>Let us now find the sum of prime factors of 2014</u></em>

sum of prime factors of 2014 = 2 + 19 + 53 = 74

Thus the sum of prime factors of 2014 is 74

7 0
3 years ago
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