Question

Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3). What is the coordinates of the image if the parallelogram is dilated with a scale factor of -1/3

Answer 1

Answer: $(\dfrac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .$

Step-by-step explanation:

Transformation rule for dilation:

$(x,y)\to(kx,ky)$ , where k = scale factor

Given : Scale factor = $-\dfrac13$

Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3)

Vertices after dilation:

$(-1,6)\to(-1\times\dfrac{-1}{3},6\times\dfrac{-1}{3})=(\dfrac13,-2)$

$(0,9)\times(0\times-\dfrac13,9\times-\dfrac13)=(0,-3)$

$(6,-3)\to(6\times-\dfrac13,\ -3\times-\dfrac13)=(-2,1)$

$(3,-3)\to (3\times-\dfrac13,\ -3\times-\dfrac13)=(-1,1)$

Hence, the coordinates of the image if the parallelogram = $(\dfrac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .$