Answer:
WHERE IS THE TABLE
Step-by-step explanation:
Y=6/(4*10)-40
y=6/40-40
y=6/0
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Answer:
Option C. No solution is the right answer.
Step-by-step explanation:
Here the given equations are y = x²+2x+3 -----(1)
and y = 4x-2 -------(2)
Now we substitute the value of y from equation 2 into 1.
x²+2x+3 = 4x-2
x²+2x+3-2x = 4x-2-2x
x²+3 = 2x-2
x²+3-2x = 2x-2x-2
x²-2x+3 = -2
x²-2x+5 = 0
Then value of 


Since in this solution √(-20) is not defined. Therefore there is no solution.
Answer:
Function
is shifted 1 unit left and 1 unit up.

Transformed function 
Step-by-step explanation:
Given:
Red graph (Parent function):

Blue graph (Transformed function)
From the graph we can see that the red graph is shifted 1 units left and 1 units up.
Translation Rules:

If
the function shifts
units to the left.
If
the function shifts
units to the right.

If
the function shifts
units to the up.
If
the function shifts
units to the down.
Applying the rules to 
The transformation statement is thus given by:

As function
is shifted 1 unit left and 1 unit up.
Transformed function is given by:

You’re answer will be “x=-2”