Answer:
it should be flat 0 degrees i think because u didnt give much to go with
Step-by-step explanation:
Answer:
The slope is 0 and y-intercept is 0
Step-by-step explanation:
The two lines met and cross each other
<h3>hello!</h3>
In order to see whether or not a point lies on the line, we need to plug in the x-coordinate (instead of x) and plug the y-coordinate instead of y.
In this case, the x-coordinate is:-
and the y-coordinate is:-
![\mathrm{-1}](https://tex.z-dn.net/?f=%5Cmathrm%7B-1%7D)
Plug in the values:-
![\mathbf{-10(1)+5(-1)=-8}](https://tex.z-dn.net/?f=%5Cmathbf%7B-10%281%29%2B5%28-1%29%3D-8%7D)
![\mathbf{-10-5=-8}](https://tex.z-dn.net/?f=%5Cmathbf%7B-10-5%3D-8%7D)
![\mathbf{-15=-8}](https://tex.z-dn.net/?f=%5Cmathbf%7B-15%3D-8%7D)
Huh?!
As you can see, we ended up with a false statement.
Hence, the answer is:-
![\bigstar{\boxed{\pmb{The~point~(1,-1)~doesn't~lie~on~the~line}}}](https://tex.z-dn.net/?f=%5Cbigstar%7B%5Cboxed%7B%5Cpmb%7BThe~point~%281%2C-1%29~doesn%27t~lie~on~the~line%7D%7D%7D)
Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I'll comment and/or edit my answer :)
Answer:
The graph of an odd function will be symmetrical about the origin. For example, f(x) = x3 is odd. That is, the function on one side of x-axis is sign inverted with respect to the other side or graphically, symmetric about the origin.