What is the value of log^7^343
1 answer:
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First, square both sides. This will cancel out the radical.
(a^2 = b + 6)
Then subtract 6 from both sides
b = a^2 - 6
(a^2 = b + 6)
Then subtract 6 from both sides
b = a^2 - 6
Answer:
Part (A) The required ways are 792.
Part (B) The required ways are 101376.
Step-by-step explanation:
Consider the provided information.
Part (A) The alphabet {a, b}
The length of strings is 12 that containing exactly five a's.
The number of ways are:
After filling "a" we have now 7 places.
For 7 places we have "a" and "b" alphabet but we already select a's so now the remaining place have to fill by "b" only.
Thus, the required ways are:
Part (B) The alphabet {a, b, c}
We have selected five a's now we have now 7 places.
For 7 places we have "b" and "c".
Thus, there are 2 choices for each 7 place that is
Therefore the total number of ways are:
Thus, the required ways are 101376.