a) C(0.5) = 39, C(2) = 39, C(4) = 69
b) Answers in part (a) represents the values of C at x = x₀
c) C(x) is continuous at x = 2
C (x) = 39 for 0 ⩽ x ⩽ 2
Since x = 0.5 is in the range 0 ⩽ x ⩽ 2:
C(0.5) = 39
Since x = 2 is in the range 0 ⩽ x ⩽ 2
C(2) = 39
Since x = 4 is in the range x > 2
C(4) = 39 + 15(x - 2)
C(4) = 39 + 15 (4 - 2)
C(4) = 39 + 15(2)
C(4) = 39 + 30
C(4) = 69
b) The answers in part A represents C(x). That is, the values of C at x = x₀
c) Is C(x) continuous at x = 2
C(2) = 39
Since 
, the function C(x) is continuous at x = 2
Learn more here: brainly.com/question/20710468
Answer:
-30a^5b + 12a^4b^3 + 16a^3b^2 - 4a^2b^4 - 2 ab^3
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
It is 0 because the slope intercept form is y=mx+b right now you only have the y intercept which is the b of the equation. That means that your slope is non existence
Answer:
y + 6 = (-8/5)(x - 1) in point-slope form
Step-by-step explanation:
Moving from the 1st point to the first, we see that x (the 'run') increases by 5 from -4 to 1, and y (the 'rise') decreases by 8. Thus, the slope of the line through these two points is m = rise / run = -8/5
Now we have two points on the line, plus the slope. Let's write out the point-slope formula for the equation of a straight line:
y - k = m(x - h), where (h, k) is a point on the line and m is the slope of the line.
Here, using the point (1, -6), we obtain:
y + 6 = (-8/5)(x - 1) in point-slope form
