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Ne4ueva [31]
3 years ago
11

HELP GEOMOTRY QUESTION

Mathematics
1 answer:
V125BC [204]3 years ago
4 0

Answer:

d) The points on the perpendicular bisector of a side of a triangle are equidistant from the  vertices of the side it bisects.

Step-by-step explanation:

By the property of perpendicular bisector, any point on the perpendicular bisector is equidistant from the end points of the segment it bisects.

For the given triangle any point on the line CD is equidistant from the vertices A and B as line CD  is the perpendicular bisector of side AB .

Thus, the statement below holds true:  

d) The points on the perpendicular bisector of a side of a triangle are equidistant from the  vertices of the side it bisects.

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(5x-6x^2y+x^2)-(-3x^2y+4x^2)
xenn [34]
(5x-6x+2y+x+2) - (-3x+2y+4x+2)
5x-6x+x=0. (x+2y+2)
(2y+2) (x+2y+2)

= 4y-x+4
5 0
3 years ago
What is the axis of symmetry of the function f(x)= -(x+9)(x-21)
tamaranim1 [39]

Answer:

The axis of symmetry is x = 6

Step-by-step explanation:

To find this, first find the two x-intercept values and then take the average. This will always be the line of symmetry.

x + 9 = 0

x = -9

x - 21 = 0

x = 21

Now take the average of these two numbers.

(-9 + 21)/2

12/2

6

5 0
3 years ago
The length of a rectangle is three more than twice its width. The perimeter is 36 inches. Find the length and width
Mandarinka [93]
Your answers are:

W= 5

L= 13


Good luck!
7 0
4 years ago
Reflect the shape over the line shown !
snow_lady [41]
This is the reflected shape can u award brainliest

7 0
2 years ago
The table below represents the distance of an airplane from its destination as a function of time:
Jlenok [28]
\bf \begin{array}{ccllll}
time(hours)&distance(miles)\\
-----&-------\\
0&2700\\
1&2160\\
2&1620\\
3&1080\\
4&540
\end{array}

part A)

y-intercept is when the graph "intercepts" or touches the y-axis, and when that happens, x = 0, on that table, is the very first row, 0, 2700.

what does that mean? well, at 0 hours, the plane was 2700 miles away.
or another way to put it, the plane was still on the runway at the airport and hadn't taken off at 0 hours, and the airport where it was is 2700 miles away from its destination.

part B)

from the table, we can see the x = 1, y = 2160, and when x = 4, y = 540,
so our two points are (1, 2160) and (4, 540).

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 1}}\quad ,&{{ 2160}})\quad 
%   (c,d)
&({{ 4}}\quad ,&{{ 540}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{540-2160}{4-1}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}
\\\\\\
\cfrac{-1620}{3}\implies \boxed{-540}

or -540/1, well the top is the rise(miles) and the bottom is the run(hours)... so it means -540 miles per each 1hour,
or
for every passing hour the plane is travelling, the distance from its origin and its destination is shrinking, namely, is getting closer to its destination.

part C)

well, we know for every hour is dropping by 540, so, 4hrs is 540, so 5hours it will drop another 540, or 540 - 540 = 0

so, the domain will be [0, 5], since after 5hours it'd be at its destination, because at 5hrs the miles away is 0, meaning it arrived at the destination.
6 0
3 years ago
Read 2 more answers
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