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Soloha48 [4]
3 years ago
12

Can someone please help me with 15?

Mathematics
1 answer:
Feliz [49]3 years ago
4 0

the answer is m=17

https://photomath.net/s/argDe9 shows how to get there

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Solve for n<br> 2/5n+3-7/10n=3/5-3n
LuckyWell [14K]
<h2>The answer is "-\frac{8}{9} \\\\".</h2>

Given:

\to \frac{2}{5}n+3-\frac{7}{10}n=\frac{3}{5}-3n

To find:

n=?

Solution:

\to \frac{2}{5}n+3-\frac{7}{10}n=\frac{3}{5}-3n\\\\\to \frac{2}{5}n-\frac{7}{10}n+3n=\frac{3}{5} -3\\\\\to n(\frac{4-7+30}{10})=\frac{3-15}{5} \\\\\to n(\frac{-3+30}{10})=\frac{3-15}{5} \\\\\to n(\frac{27}{10})=\frac{-12}{5} \\\\\to n=\frac{-12}{5} \times \frac{10}{27} \\\\\to n=-4 \times \frac{2}{9} \\\\\to n=-\frac{8}{9} \\\\

Therefore, the final answer of n is "-\frac{8}{9} \\\\".

Find out more information about solving here:

brainly.com/question/322601

7 0
3 years ago
Put the quadratic into vertex form and state the coordinates of the vertex. y= y= \,\,x^2-6x-3 x 2 −6x−3
enot [183]

Answer:

y = (x - 3)^2 - 12

(3,-12)

Step-by-step explanation:

Given

y = x^2 - 6x - 3

Solving (a): In vertex form

The vertex form of an equation is:

y = a(x - h)^2 + k

To do this, we make use of completing the square method.

We have:

y = x^2 - 6x - 3

------------------------------------------------------------------

Take the coefficient of x (i.e. -6)

Divide by 2; -6/2 = -3

Square it: (-3)^2 = 9

Add and subtract the result to the equation

------------------------------------------------------------------

y = x^2 - 6x - 3

y = x^2 - 6x + 9 - 9 - 3

y = x^2 - 6x + 9 - 12

Factorize x^2 - 6x + 9

y = x^2 - 3x-3x + 9 - 12

y = x(x - 3)-3(x - 3) - 12

Factor out x - 3

y = (x - 3)(x - 3) - 12

Express as squares

y = (x - 3)^2 - 12

Hence, the vertex form of y = x^2 - 6x - 3 is: y = (x - 3)^2 - 12

Solving (b): State the coordinates of the vertex.

In y = a(x - h)^2 + k; the vertex is: (h,k)

The vertex of y = (x - 3)^2 - 12 will be (3,-12)

3 0
3 years ago
What is the solution to | 2x-4| &gt;8?
Serga [27]
| 2x-4| \ \textgreater \ 8 \\ \\ 2x - 4 \ \textgreater \  8 \ , \ -(2x - 4) \ \textgreater \  8 \ / \ break \ problem \ into \ 2 \ equations \\ \\ first \ equation  \\ \\ 2x \ \textgreater \  8 + 4 \ / \ add \ 4 \ to \ each \ side \\ \\ 2x \ \textgreater \  12 \ / \ simplify \\ \\ x \ \textgreater \   \frac{12}{2} \ / \ divide\ each \ side \ by \ 2 \\ \\ x \ \textgreater \  6 \ / \ simplify \\ \\ second \ equation \\ \\ -2x + 4 \ \textgreater \  8 \ / \ simplify \\ \\ -2x \ \textgreater \  8 - 4 \ / \ subtract \ 4 \ from \ each \ side \\ \\ -2x \ \textgreater \  4 \ / \ simplify \\ \\  x \ \textless \   \frac{4}{-2} \ / \ divide \ each \ side \ by \ -2 \\ \\ 
\\ \\ x \ \textless \  -  \frac{4}{2} \ / \ simplify \\ \\ x \ \textless \  - 2 \ / \ simplify \\ \\ collect \ solutions \\ \\ x \ \textgreater \  6 \ , \ x \ \textless \  -2 \\ \\

So, your answer to this problem is x > 6 and x < -2.
8 0
3 years ago
If sin just answer the please lol i don't feel like typing<br><br> ASAP
yaroslaw [1]

Considering that the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.

<h3>What are the signs of the sine and of the cosine in each quadrant?</h3>

  • Quadrant 1: Both positive.
  • Quadrant 2: Sine positive, cosine negative.
  • Quadrant 3: Both negative.
  • Quadrant 4: Sine negative, cosine positive.

Hence, since the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.

More can be learned about quadrants at brainly.com/question/28021191

#SPJ1

5 0
2 years ago
Divisor of number <br>6? ​
mash [69]

Answer:

1 2 3 6

Step-by-step explanation:

1x6=6

2x3=6

3x2=6

6x1=6

6 0
3 years ago
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