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Brut [27]
3 years ago
8

When a number x is multiplied by 9, the result is 35 .

Mathematics
2 answers:
Inga [223]3 years ago
7 0

X should be equal to four. You divide 35 by 9 to get the answer (x=4)

Dvinal [7]3 years ago
3 0

Answer:  The required value of x is 3\dfrac{8}{9}.

Step-by-step explanation:  Given that when a number x is multiplied by 9, the result is 35 .

We are to find the value of x.

According to the given information, the equation can be written as :

9\times x=35\\\\\Rightarrow 9x=35.

The solution of the above equation is as follows :

9x=35\\\\\Rightarrow x=\dfrac{35}{x}\\\\\Rightarrow x=3\dfrac{8}{9}.

Thus, the required value of x is 3\dfrac{8}{9}.

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dimulka [17.4K]

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hope this helps

3 0
3 years ago
Pls help if pls do most important 15 number 20 number 26 number 28 number 30 number 17 number 25 number 22 number 24 number if u
Tamiku [17]

Answer:

Step-by-step explanation:

15. \frac{cotx+1}{cotx-1} = \frac{cotx+cotx.tanx}{cotx-cotx.tanx} = \frac{cotx(1+tanx)}{cotx(1-tanx)} = \frac{1+tanx}{1-tanx}   \\

16.  \frac{1+cos\alpha }{sin\alpha } = \frac{sin\alpha }{1-cos\alpha }

=> (1+cos\alpha )(1-cos\alpha ) = sin^{2} \alpha \\=> 1-cos^{2}\alpha =sin^{2}  \alpha \\=> sin^{2}\alpha +cos^{2}\alpha =1\\

=> The clause is correct

17. Do the same (16)

18. \frac{sinx}{1-cosx}+\frac{sinx}{1+cosx} = \frac{sinx(1+cosx) + sinx(1-cosx)}{(1+cosx)(1-cosx)} = \frac{sinx + sinx.cosx + sinx - sinx.cosx}{1-cos^{2}x} = \frac{2sinx}{sin^{2}x }= \frac{2}{sinx} = 2cosecx

19.

\frac{sinA}{1+cosA} + \frac{1+cosA}{sinA}=\frac{2}{sinA} \\=> \frac{sinA}{1+cosA} + \frac{1+cosA}{sinA} - \frac{2}{sinA} \\ = 0\\=> \frac{sinA}{1+cosA} + (\frac{1+cosA}{sinA} - \frac{2}{sinA} \\) = 0\\=> \frac{sinA}{1+cosA} + \frac{1+cosA-2}{sinA} = 0\\=> \frac{sinA}{1+cosA} +\frac{cosA-1}{sinA} = 0\\=> \frac{sin^{2} A+(cosA-1)(1+cosA)}{(1+cosA)sinA}=0\\=> \frac{sin^{2} A+cos^{2} A-1}{(1+cosA)sinA}=0\\=> \frac{0}{(1+cosA)sinA} =0\\

=> The clause is correct

20. Do the same (18)

21. Left = \frac{1}{cosecA+cotA} = \frac{1}{\frac{1}{sinA}+\frac{cosA}{sinA}  } = \frac{1}{\frac{1+cosA}{sinA} }= \frac{sinA}{1+cosA}

Right = cosecA-cotA = \frac{1}{sinA}-\frac{cosA}{sinA}= \frac{1-cosA}{sinA}   \\

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22. Do the same (21)

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3 years ago
Bag a contains 4 red and 3 blue tickets. bag b contains 3 red and 1 blue ticket. a bag is randomly selected by tossing a coin an
nikdorinn [45]
It's difficult to draw a tree diagram with this software.
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If A is selected (P(A) =1/2) we can get ether red (p(A & red)=4/7
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6 0
3 years ago
1
NikAS [45]

9514 1404 393

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The required force is ...

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