Answer:
Step-by-step explanation:
The given quadratic function is f(x)=2(2x^2+4x)+3
Multiplying through to open the brackets,
f(x)=4x^2 + 8x +3
To find the zeros, we will equate
f(x) = 0
Therefore,
4x^2 + 8x +3 = 0
Finding two numbers such that when we multiply them, it gives us 12xx^2 and when we add them, it gives us 8x, we have 6x and 2x. Therefore,
4x^2 + 8x +3 = 0 is expressed as
4x^2 + 2x + 6x +3 = 0
2x(2x + 2) +3(2x + 3) = 0
(2x +2)(2x +3) =0
f(x) = 2x +2)(2x +3)
