Question

The sum of 3 consecutive even integers is 408. find the integers

Answer 1

Let n be the unknown value

n + (n+2) + (n+4) = 408

Then we would simplify by combining like terms

n + n + 2 + n + 4 = 408

3n+6=408
     -6     -6
--------------
3n=402

Divide. 

3n=402
--    ----
3      3

n = 134. 
So the first integer is 134. Then plug in the rest to the n+2 and n+4

134+2= 136
134+4= 138

The integers are then 134, 136, 138