The sum of 3 consecutive even integers is 408. find the integers

1 answer:

4 0

Let n be the unknown value

n + (n+2) + (n+4) = 408

Then we would simplify by combining like terms

n + n + 2 + n + 4 = 408

3n+6=408
-6 -6
--------------
3n=402

Divide.

3n=402
-- ----
3 3

n = 134.
So the first integer is 134. Then plug in the rest to the n+2 and n+4

134+2= 136
134+4= 138

The integers are then 134, 136, 138

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