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2 years ago

Calculate each quotient. Write your answers in lowest terms.

Mathematics

1 answer:

pochemuha2 years ago

5 0

AnswerReanswer into right and left in going to the man

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Simplify (3x^-2y^4)^-3

Anuta_ua [19.1K]

Answer:

x^6/27y^12

Step-by-step explanation:

(3. 1?x^2 y^4)^3

(3y^4/x^2)^3

witch you get x^6/27y^12

hope i helped

5 0

2 years ago

I need an answer ASAP pls

tino4ka555 [31]

Answer:

Age 42 salary 30,000

Step-by-step explanation:

He had to restart his medical training, therefore, making him have a lower salary regardless of his age, making this point an obvious outlier

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3 years ago

112 is 70% of _______

aliina [53]

Answer:

160

Step-by-step explanation:

70% of 160=112.

A handy trick is to divide the number by the percentage.

Brainliest please I need those points.

8 0

2 years ago

Read 2 more answers

The price p of a pizza is $6.95 plus $.95 for each topping t on the pizza

Grace [21]

The price would come out to be about 8 dollars if you are looking for whole numbers the original answer is 7.9 if I got this wrong I am sorry I did know the # of toppings

6 0

2 years ago

Hello people ~

Luden [163]

Cone details:

height: h cm

radius: r cm

Sphere details:

radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

Using Pythagoras Theorem

(a)

TO² + TU² = OU²

(h-10)² + r² = 10² [insert values]

r² = 10² - (h-10)² [change sides]

r² = 100 - (h² -20h + 100) [expand]

r² = 100 - h² + 20h -100 [simplify]

r² = 20h - h² [shown]

r = √20h - h² ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (\sqrt{20h - h^2})^2 \ ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20h - h^2) (h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20 - h) (h) ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)$

To find maximum/minimum, we have to find first derivative.

(c)

First derivative

$\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )$

apply chain rule

$\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}$

Equate the first derivative to zero, that is V'(x) = 0

$\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0$

$\Longrightarrow \sf 40h-3h^2=0$

$\Longrightarrow \sf h(40-3h)=0$

$\Longrightarrow \sf h=0, \ 40-3h=0$

$\Longrightarrow \sf h=0,\:h=\dfrac{40}{3}$

maximum volume: when h = 40/3

$\sf \Longrightarrow max= \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )$

$\sf \Longrightarrow maximum= 1241.123 \ cm^3$

minimum volume: when h = 0

$\sf \Longrightarrow min= \dfrac{1}{3} \pi (0)^2(20-0)$

$\sf \Longrightarrow minimum=0 \ cm^3$

6 0

1 year ago

Read 2 more answers