We are given statement 3.59 > 3.5__1 >3.572.
We have a blank space in between 5 and 1 in the middle number given.
Given statement ccan be read as :
3.59 is greater than 3.5__1 is greater than 3.572.
So, we need to check a number that is less than 3.59 but less than 3.572.
The hundredth place of 3.59 number is 9 and
hundredth place of 3.572 number is 7.
So, we need to find a number between 7 and 9.
8 is the number in between 7 and 9.
So, the known digit can be replaced by 8 to make the statement true.
And final statement is 3.59 > 3.581 >3.572.
Yes, you are right. the length is 3, the height is 2, and the width is 1
Answer: -1/2
Step-by-step explanation:
Slope is change in y over change in x. Y shifts down -1, while X shifts to the right 2
Answer:
c
Step-by-step explanation:
2.8.1

By definition of the derivative,

We have

and

Combine these fractions into one with a common denominator:

Rationalize the numerator by multiplying uniformly by the conjugate of the numerator, and simplify the result:

Now divide this by <em>h</em> and take the limit as <em>h</em> approaches 0 :

3.1.1.
![f(x) = 4x^5 - \dfrac1{4x^2} + \sqrt[3]{x} - \pi^2 + 10e^3](https://tex.z-dn.net/?f=f%28x%29%20%3D%204x%5E5%20-%20%5Cdfrac1%7B4x%5E2%7D%20%2B%20%5Csqrt%5B3%5D%7Bx%7D%20-%20%5Cpi%5E2%20%2B%2010e%5E3)
Differentiate one term at a time:
• power rule


![\left(\sqrt[3]{x}\right)' = \left(x^{1/3}\right)' = \dfrac13 x^{-2/3} = \dfrac1{3x^{2/3}}](https://tex.z-dn.net/?f=%5Cleft%28%5Csqrt%5B3%5D%7Bx%7D%5Cright%29%27%20%3D%20%5Cleft%28x%5E%7B1%2F3%7D%5Cright%29%27%20%3D%20%5Cdfrac13%20x%5E%7B-2%2F3%7D%20%3D%20%5Cdfrac1%7B3x%5E%7B2%2F3%7D%7D)
The last two terms are constant, so their derivatives are both zero.
So you end up with
