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Vanyuwa [196]
3 years ago
11

Write a program named CheckMonth that prompts a user to enter a birth month. If the value entered is greater than 12 or less tha

n 1, display the error message Invalid month; otherwise, display the valid month with a message such as 3 is a valid month.
Computers and Technology
1 answer:
klemol [59]3 years ago
3 0

Answer:

Program:

month=['January', 'Februrary', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December'] #list which stores the name of the month.

CheckMonth= int(input("Enter the number of the month")) #it is used to take the inputs from the user.

if CheckMonth>=1 and CheckMonth<=12: #check the condition for valid month.

   print(str(CheckMonth)+" is a valid month which name is: "+ str (month [CheckMonth-1])) #print the name of month which is enter by the user.

else:

   print(str(CheckMonth)+" is not a valid month, please enter the valid month") # print for the invalid month.

Output:

  • If the user inputs 1, it will prints "1 is a valid month which name is: January".
  • If the user inputs is 0, then it will prints "0 is not a valid month, please enter the valid month"

Explanation:

  • The above program is in python language, in which the first line of the code is used to hold the list of the month.
  • Then the second line is used to render a message for the user input, take the input from the user and save it into a variable.
  • Then that value is checked by the if-condition that it lies in between 1 to 12 or not.
  • If it lies, then print the valid month otherwise it prints that the month is invalid.
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Answer:

Following are the solution to this question:

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Explanation:

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3 years ago
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Answer:

The answer is below

Explanation:

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Binary is a base-2 number system instead of the decimal (base-10) system we are familiar with. Write a recursive function PrintI
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Answer:

In C++:

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if (num == 0)  

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Explanation:

This defines the PrintInBinary function

int PrintInBinary(int num){

This returns 0 is num is 0 or num has been reduced to 0

<em> if (num == 0)  </em>

<em>  return 0;  </em>

If otherwise, see below for further explanation

<em> else </em>

<em>  return (num % 2 + 10 * PrintInBinary(num / 2)); </em>

}

----------------------------------------------------------------------------------------

num % 2 + 10 * PrintInBinary(num / 2)

The above can be split into:

num % 2 and + 10 * PrintInBinary(num / 2)

Assume num is 35.

num % 2 = 1

10 * PrintInBinary(num / 2) => 10 * PrintInBinary(17)

17 will be passed to the function (recursively).

This process will continue until num is 0

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