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Advocard [28]
3 years ago
9

what european cultural practice was considered barbaric to the chinese? a) keeping one's hands bare b) wearing hats indoors c) p

ublic physical contact d) males wearing pants
Mathematics
2 answers:
Elza [17]3 years ago
6 0

Lack of Personal HYgene


SVETLANKA909090 [29]3 years ago
3 0
Answer – C. (public physical contact)
 The European cultural practice of making physical contact in the public (for instance, shaking hands, holding hands or giving a hug) was considered barbaric to the Chinese. In Chinese culture and tradition, physical contact and touch should be minimized in public, even among the same sex. <span>
</span>
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Two column proof:
gulaghasi [49]

Answer:

Given : BRDG is a kite that is inscribed in a circle,

With BR = RD and BG = DG

To prove : RG is a diameter

Proof:

Since, RG is the major diagonal of the kite BRDG,

By the property of kite,

∠ RBG = ∠ RDG

Also, BRDG is a cyclic quadrilateral,

Therefore, By the property of cyclic quadrilateral,

∠ RBG + ∠ RDG = 180°

⇒ ∠ RBG + ∠ RBG = 180°

⇒ 2∠ RBG = 180°

⇒ ∠ RBG = 90°

⇒ ∠ RDG = 90°

Since, Angle subtended by a diameter or semicircle on any point of circle is right angle.

⇒ RG is the diameter of the circle.

Hence, proved.

8 0
3 years ago
What is the graph of y=-(x-2)^3-5
natulia [17]
When x=0,
y=-(0-2)^3-5
y=3

When y=0,
(x-2)^3=5
x-2= +/- 5^1/3
x= +/- 5^1/3 +2
x= 3.70997 or x=0.29002

To find the turning point at y, substitute the information that you have found above.

y=-(3.70997-2)^3-5
y=-9.99994

Find the mid-point next as mid-point is also the turning point.

(3.70997+0.29002)÷2=1.999995

Hence, Turning point is (1.999995, 9.99994)

Plot a graph using turning point, y value and the 2-x values.
6 0
3 years ago
CONVERT 2930 TO BASE FIVE
prohojiy [21]
Hello

The answer is <span>43210<span>5

Have a nice day</span></span>
5 0
3 years ago
A cylindrical tank has a base of diameter 12 ft and height 5 ft. The tank is full of water (of density 62.4 lb/ft3).(a) Write do
saw5 [17]

Answer:

a.  71884.8 π lb/ft-s²∫₀⁵(9 - y)dy

b.  23961.6 π lb/ft-s²∫₀⁵(5 - y)dy

c. 99840π lb/ft-s²∫₀⁶rdr

Step-by-step explanation:

.(a) Write down an integral for the work needed to pump all of the water to a point 4 feet above the tank.

The work done, W = ∫mgdy where m = mass of cylindrical tank = ρA([5 + 4] - y) where ρ = density of water = 62.4 lb/ft³, A = area of base of tank = πd²/4 where d = diameter of tank = 12 ft.( we add height of the tank + the height of point above the tank and subtract it from the vertical point above the base of the tank, y to get 5 + 4 - y) and g = acceleration due to gravity = 32 ft/s²

So,

W = ∫mgdy

W = ∫ρA([5 + 4] - y)gdy

W = ∫ρA(9 - y)gdy

W = ρgA∫(9 - y)dy

W = ρgπd²/4∫(9 - y)dy

we integrate W from  y from 0 to 5 which is the height of the tank

W = ρgπd²/4∫₀⁵(9 - y)dy

substituting the values of the other variables into the equation, we have

W = 62.4 lb/ft³π(12 ft)² (32 ft/s²)/4∫₀⁵(9 - y)dy

W = 71884.8 π lb/ft-s²∫₀⁵(9 - y)dy

.(b) Write down an integral for the fluid force on the side of the tank

Since force, F = ∫PdA where P = pressure = ρgh where h = (5 - y) since we are moving from h = 0 to h = 5. So, P = ρg(5 - y)

The differential area on the side of the tank is given by

dA = 2πrdy

So.  F = ∫PdA

F = ∫ρg(5 - y)2πrdy

Since we are integrating from y = 0 to y = 5, we have our integral as

F = ∫ρg2πr(5 - y)dy

F = ∫ρgπd(5 - y)dy    since d = 2r

substituting the values of the other variables into the equation, we have

F = ∫₀⁵62.4 lb/ft³π(12 ft) × 32 ft/s²(5 - y)dy

F = 23961.6 π lb/ft-s²∫₀⁵(5 - y)dy

.(c) How would your answer to part (a) change if the tank was on its side

The work done, W = ∫mgdr where m = mass of cylindrical tank = ρAh where ρ = density of water = 62.4 lb/ft³, A = curved surface area of cylindrical tank = 2πrh  where r = radius of tank, d = diameter of tank = 12 ft. and h =  height of the tank = 5 ft and g = acceleration due to gravity = 32 ft/s²

So,

W = ∫mgdr

W = ∫ρAhgdr

W = ∫ρ(2πrh)hgdr

W = ∫2ρπrh²gdr

W = 2ρπh²g∫rdr

we integrate from r = 0 to r = d/2 where d = diameter of cylindrical tank = 12 ft/2 = 6 ft

So,

W = 2ρπh²g∫₀⁶rdr

substituting the values of the other variables into the equation, we have

W = 2 × 62.4 lb/ft³π(5 ft)² × 32 ft/s²∫₀⁶rdr

W = 99840π lb/ft-s²∫₀⁶rdr

7 0
3 years ago
Simplify 3x-2+x+3 *<br><br> What is the answer?
alexandr402 [8]

Answer:

Step-by-step explanation:

4x

And in distributive property it would be

3x-2x+3

6 0
3 years ago
Read 2 more answers
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