The answer is that they do not live on or in the body of a host.
Depends if they have some of the same genetic structures
Answer:
Ss and ss
Explanation:
<em>Since the smooth trait (S) is dominant over the wrinkle trait (s), the genotype of the wrinkled pea parent is definitely </em><em>ss</em><em>.</em>
<em>Also, some of the progeny had wrinkled pea texture (ss). Each of the 2 wrinkled alleles must have been donated by each of the parent. It thus means that the smooth pea parent is heterozygous for the trait (</em><em>Ss</em><em>).</em>
Now, let us look at a cross between the two parents;
Ss x ss
Progeny: Ss, Ss, ss, ss.
Phenotypically, 50% of the progeny are smooth peas while 50% are wrinkled.
Looking at the population of each of the phenotype resulting from the cross. 252:247 is approximately a 50:50 ratio.
Hence, the genotypes of the two parents are Ss and ss.
Answer:
The correct answer is iron-transport proteins
Explanation:
Siderophores are proteins produced by bacteria, and compete with the host's iron-transport proteins. They aim to bind and "hijack" the host's cell iron molecules for their own pathogenic cell processes
