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3 years ago

13

Rosana construindo um galinheiro no fundo de sua residencia utilizou 4 galoes para o transporte do material. Um dos galoes era f

ragil e nao aguentou. Qual galão nao aguentou ?
a o de agua
b o de massa
c o de brita
d o de areia

1 answer:

LiRa [457]3 years ago

7 0

Question: Rosana building a chicken coop at the bottom of your residencia used 4 gallons for the transport of the material. One of gallons was fragile and not make it. What gallon not stand it? (a) the water
(b) the mass of c the brita
(d) the sand Answer: B) the mass of c the brita

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Can you help me with this math problem and tell me how to do it?

Gemiola [76]

Let the number of songs Lou has = X

Kelly has 4 times as many as Lou, which would be written as 4X

Tiffany has 6 times as many songs as Lou, which would be written as 6X

The total number of songs = 682

You need to add all three people together to equal 682

So you would get:

X + 4X + 6X = 682 songs.

Combine all like terms ( 6x + 4x + X = 11x)

11x = 682

Now to solve for X divide both sides by 11:

x = 682 / 11 = 62

Lou = x = 62 songs.

Kelly = 4x = 4(62) = 4*62 = 248 songs.

Tiffany = 6x = 6(62) = 6 *62 = 372 songs.

7 0

3 years ago

Convert the function into standard form. Show your work. y-2=-3(x+4)^2

Sonja [21]

Answer:

y = -3x² - 24 x + 50

Step-by-step explanation:

y - 2 = - 3(x+4)²

y - 2 = -3(x²+8x+16)

y - 2 = -3x² -24x +48

y = -3x² - 24 x + 50

8 0

3 years ago

Read 2 more answers

During optimal conditions, the rate of change of the population of a certain organism is proportional to the population at time

Lana71 [14]

Answer:

The population is of 500 after 10.22 hours.

Step-by-step explanation:

The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

$\frac{dP}{dt} = Pr$

In which r is the growth rate.

Solving by separation of variables, then integrating both sides, we have that:

$\frac{dP}{P} = r dt$

$\int \frac{dP}{P} = \int r dt$

$\ln{P} = rt + K$

Applying the exponential to both sides:

$P(t) = Ke^{rt}$

In which K is the initial population.

At time t = 0 hours, the population is 300.

This means that K = 300. So

$P(t) = 300e^{rt}$

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

$P(t) = 300e^{rt}$

$1000 = 300e^{24r}$

$e^{24r} = \frac{1000}{300}$

$e^{24r} = \frac{10}{3}$

$\ln{e^{24r}} = \ln{\frac{10}{3}}$

$24r = \ln{\frac{10}{3}}$

$r = \frac{\ln{\frac{10}{3}}}{24}$

$r = 0.05$

So

$P(t) = 300e^{0.05t}$

At what time t is the population 500?

This is t for which P(t) = 500. So

$P(t) = 300e^{0.05t}$

$500 = 300e^{0.05t}$

$e^{0.05t} = \frac{500}{300}$

$e^{0.05t} = \frac{5}{3}$

$\ln{e^{0.05t}} = \ln{\frac{5}{3}}$

$0.05t = \ln{\frac{5}{3}}$

$t = \frac{\ln{\frac{5}{3}}}{0.05}$

$t = 10.22$

The population is of 500 after 10.22 hours.

7 0

3 years ago

What is the length of AB? A.2.59 B.9.66 C.10.35 D38.64

Jlenok [28]

Answer:

what

Step-by-step explanation:

is the questionn

5 0

3 years ago

Write each fraction or mixed number as a decimal. Use bar notation if needed

iragen [17]

There you good luck with everything

7 0

3 years ago