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shusha [124]
4 years ago
6

Expand and simplify these

Mathematics
1 answer:
Effectus [21]4 years ago
6 0
(x+6)(x+9)=x^2+9x+6x+54=x^2+15x+54 \\\\(x-5)(x+2)=x^2+2x-5x-10=x^2-3x-10\\\\(x-1)(x-7)=x^2-7x-x+7=x^2-6x+7\\\\(4x+9)(3x+8)=12x^2+32x+27x+72=12x^2+59x+72\\\\(3x-8)(2x-1)=6x^2-3x-16x+8=6x^2-19x+8\\\\(x+9) ^2=x^2+2\cdot x\cdot9+9^2=x^2+18x+81 \\\\(3x+2)^2=(3x)^2+2\cdot3x\cdot2+2^2=9x^2+12x+4
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If log (m + n) = log m+ log n

To show that the m =n/n-1​

Now, According to the question:

We know that,

Log (m + n) = log m + log n

Log (m + n ) = log (mn).                 [log a + log b = log ab ]

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then,

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A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.

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