Edward can run 1/2 mile in 300 seconds what is edwards unit rate
1 answer:
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Question 1)
The given parabola is:
First we need to convert this equation to the general form similar to:
So, the given equation will be:
Comparing given equation with the general equation, we can write:
p = 2
h = -12
k= -16
The focus of the parabola with squared x terms lies at (h , k+p)
Using the values, we get the focus point of the given parabola (-16, -10)
Question 2.
The equation of the parabola is:
This means:
p=4
h = -3
k =1
The directrix of the parabola with squared y term has the equation of the form:
x = h - p
Using the values, we get
x= - 3 - 4 = -7
So, the equation of the directrix of the parabola will be x = -7
The given parabola is:
First we need to convert this equation to the general form similar to:
So, the given equation will be:
Comparing given equation with the general equation, we can write:
p = 2
h = -12
k= -16
The focus of the parabola with squared x terms lies at (h , k+p)
Using the values, we get the focus point of the given parabola (-16, -10)
Question 2.
The equation of the parabola is:
This means:
p=4
h = -3
k =1
The directrix of the parabola with squared y term has the equation of the form:
x = h - p
Using the values, we get
x= - 3 - 4 = -7
So, the equation of the directrix of the parabola will be x = -7