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4 years ago

Can some one plz answer this i can not find this out

Mathematics

2 answers:

True [87]4 years ago

8 0

The line of best fit is a line on a scatter plot graph with equal number of points on either side of it, it is the equivalent of average.

the line of best fit on your graph predicts the average score of a student who studies for 2 hours is 16

brilliants [131]4 years ago

4 0

The line of best fit is drawn for you in red.

Look up 2 hours on the x-axis.
Now move vertically up until you reach the read line, and then look horizontally to the left until you reach the y-axis. 2 hours corresponds to 16 on the y-axis.

Answer: According to the line of best fit, a student who studies 2 hours should get a score of 16. Choice A. 16

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What is the pressure in atmospheres exerted by a 0.500 mole sample of nitrogen gas in a 10.0 L container at 25.0°C?

drek231 [11]

Answer:

1.2218 atm

Step-by-step explanation:

From ideal gas formula,

PV=nRT

Where n= number of moles

V= volume

T= temperature=25.0°C

= (273 + 25) = 298 K

R= gas constant = 0.082 l atm /K mol.

Making P subject of formula we have

P= [nRT] /V

Then substitute the values we have

P= [0.5 x 0.082 x 298] / 10

P= 1.2218 atm

6 0

3 years ago

Whats -0.25 as a fraction

jonny [76]

-0.25 would be -25/100 which can be reduced to -1/4

3 0

3 years ago

Question

yuradex [85]

Answer:

(30, ∞)

Step-by-step explanation:

b – 27 > 3

Add 27 to both sides

b > 30

In interval notation

(30, ∞)

8 0

3 years ago

Read 2 more answers

Which is bigger?83 ft or 786 in?

Rom4ik [11]

83 FT Because if you divide 786 by 12 (Which is how many inches are in a foot) you will get 65.5 ft.

8 0

3 years ago

Read 2 more answers

A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)

Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

$36^6$

possible passwords.

Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

$5\cdot 36^5$

possible passwords.

So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

$\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}$

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

$P(A)=P(B)=\dfrac{5}{36}$

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

$axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8$