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Archy [21]
4 years ago
12

Turning up the transmit power or utilizing a high gain antenna to reach wireless users from a distance increases your exposure t

o
Computers and Technology
1 answer:
Sholpan [36]4 years ago
8 0
Turning up the transmit power or utilizing a high gain antenna to reach wireless users from  distance increases your exposure to radiofrequency radiation.
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A_________ formal access control methodology used to assign a level of confidentiality to an information asset and thus restrict
Illusion [34]

Answer:

1. Data classification scheme

Explanation:

<h2><u>Choose an answer from the options. </u></h2>

A<u> data classification scheme</u> formal access control methodology used to assign a level of confidentiality to an information asset and thus restrict the number of people who can access it

6 0
4 years ago
<img src="https://tex.z-dn.net/?f=%28a%20%2B%20b%29%20%20%7B2%7D" id="TexFormula1" title="(a + b) {2}" alt="(a + b) {2}" align
MariettaO [177]

Answer:

ab2

Explanation:

3 0
3 years ago
Which command will display a list of files and subdirectories in a directory?
sattari [20]
Ls -R

man ls




----------------------
3 0
4 years ago
20. The time for the disk arm to move the heads to the cylinder containing count
dolphi86 [110]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The answer is the seek time.

The seek time is the time for the disk arm to move the heads to the cylinder containing the desired sector.

5 0
3 years ago
Consider an implementation of the instruction set architecture P1 has a clock rate of 4.8 GHz and CPIs (Cycles Per Instruction)
Anestetic [448]

Answer:

a) 3.3

b) 3

Explanation:

1)

As we know ,

CPI = sum of ( instructions× clock cycle)

     = 50%(1) + 30%(4) + 20%(8)

    = 50% + 120% + 160%

    = 330%

    = \frac{330}{100} = 3.3

⇒CPI = 3.3

2)

Let a = number of cycles on average

As given,

a 10% improvement in performance of P1,

⇒New CPI = 3

⇒3 = 50% + 30% (x) + 20%(8)

⇒3 = 50% + 30% (x) + 160%

⇒3 = 210% + 30%(x)

⇒3 = 2.1 + 0.3x

⇒3 - 2.1 = 0.3x

⇒0.9 = 0.3x

⇒x = \frac{0.9}{0.3} = 3

⇒x = 3

∴ we get

Number of cycles on average = 3

6 0
3 years ago
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