The logarithmic function starts in quadrant 4 and curves up into quadrant 1 if that’s what you’re asking.
I assume the equation is

then let
.


The right side is real-valued and positive, and only on the left side do we have an imaginary term, which tells us

Then




but again we omit the negative solution, so that

Answer:
b
Step-by-step explanation:
cause it is