Answers? Or a hint please I’m begging
1 answer:
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Answer:
The area of this triangle is about 21.2132 square units.
Step-by-step explanation:
First, find the lengths of the legs AB and BC.
Length of AB ===
Find the difference in position vertically:
The points are 6 units apart vertically.
Find the difference in position horizontally:
The points are 3 units apart horizontally.
These lengths form a right triangle with the distance between the points as the hypotenuse, so you can use the pythagorean theorem to solve:
AB is about 6.7082 units long.
Length of BC ===
Same process as above.
Find the vertical distance:
2 units apart vertically.
Find the horizontal distance:
6 units apart horizontally.
Use the pythagorean theorem:
BC is about 6.3246 units long.
Area ===
Finally, you can use these to find the area of the triangle. The area of a right triangle is just half the area of a rectangle with the same base and height:
The area of this triangle is about 21.2132 square units.
