How do you solve even number between 300 and 400 it is divisible by both 5 and 9 how you solve it

Mathematics

1 answer:

BigorU [14]3 years ago

6 0

The correct answer would be 360. you go through the multiples of 5 and 9

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You charge people $10 per hour to pick fruits and $8 per hour

Aleks04 [339]

Fruits :
Y=10(h)

Flowers;
Y=8(h)

Given: h=6

Fruits:
10(6) = $60

Flowers:
8(6)= $48

Back to the question, how much more from picking fruits?

$60 - $48 = $12 more picking fruits.

Hope this helps!

8 0

3 years ago

The questions below walk through the use of kNN to predict the value of Y for a new point with (X1, X2)=(4, 4). Distance is calc

Nady [450]

Answer:

The Euclidean distance between the two given points is $\sqrt{2}\text{ units}$ .

Step-by-step explanation:

K-NN is used to predict the variable y for a new point with $(X_1,X_2) = (4,4)$

Distance is calculated in the Euclidean sense.

The Euclidean distance between two points is given by the formula:

$\text{Points: }(X_1, X_2), (x_1,x_2)\\\\D = \sqrt{{(x_2-X_2)}^2 + (x_1-X_1)^2}$

The point is $(x_1,x_2) = (3,5)$

The Euclidean distance between the two points is given by:

$D = \sqrt{(5-4)^2 + (3-4)^2} = \sqrt{2}\text{ units}$

Thus, the Euclidean distance between the two given points is $\sqrt{2}\text{ units}$ .

5 0

3 years ago

Find z 1 ÷ z 2 for z 1 = 9(cos225° + isin225°) and z 2 = 3(cos45° + isin45°).

olga nikolaevna [1]

$\bf \qquad \textit{division of two complex numbers} \\\\ \cfrac{r_1[cos(\alpha)+isin(\alpha)]}{r_2[cos(\beta)+isin(\beta)]}\implies \cfrac{r_1}{r_2}[cos(\alpha - \beta)+isin(\alpha - \beta)] \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \begin{cases} z1=9[cos(225^o)+i~sin(225^o)]\\\\ z2=3[cos(45^o)+i~sin(45^o)] \end{cases}\implies \cfrac{z1}{z2}\implies \cfrac{9[cos(225^o)+i~sin(225^o)]}{3[cos(45^o)+i~sin(45^o)]} \\\\\\ \cfrac{9}{3}[cos(225^o-45^o)+isin(225^o-45^o)]\implies 3[cos(180^o)+i~sin(180^o)] \\\\\\ 3[(-1)+i~(0)]\implies -3+0i$