<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
What is the distance between a point at (-3,4) and a point at (2,-5) ?
<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
Let the two points be A and B .
And, let the distance be P .
Now, the distance P between the point A (-3,4) and the point B (2,-5) is




<h3>The distance between a point at (-3,4) and a point at (2,-5) is <u>1</u><u>0</u><u>.</u><u>3</u> . [Answer]</h3>
Answer:
d = -280 m
Step-by-step explanation:
Given that,
Velocity of Andre, v = -8 m/s
Time taken, t = 35 seconds
We need to find his finishing position. Let the finishing position be x.
We know that,
Velocity = distance/time
So,

so, he was at a distance of 280 m in west.
Answer:
150×500=30, i got you man
<h2>Good morning
,</h2>
<em><u>Answer</u></em>:
The quadratic equation is : x²+x+1=0
<u><em>Step-by-step explanation:</em></u>
Generally:
let S be the sum of the roots z₁ and z₂
and P be the product of the roots z₁ and z₂
then z₁ and z₂ are the solutions for the equation: x² − Sx + P = 0
Now,
S=-1 and P=1 then the equation is x²+x+1=0.
______
:)