<span>Dayson has 1 m2 of wrapping paper, which is 10000 cm2:
1 m = 100 cm
1 m^2 = (100 cm)^2
</span>1 m^2 = 10000 cm^2
<span>The package has a surface area of cm2:
A = 2*(50*20) + </span>2*(50*18) + 2*(18*20)
A = <span>
<span>4520 cm^2
</span></span>The area of the package is less than the area of the wrapping paper (4520 cm^2 < 10000 cm^2<span>). So, Dayson cover the package with the wrapping paper.</span>
Answer:
39/56
Step-by-step explanation:
When you add fractions, both of the base numbers (denominators) have to be the same number in order to add the top numbers (numerators).
The easiest way to do this is to multiply each denominator by the other number. For example, 8 * 7 and 7 * 8. So you will have 56 and 56. You also need to multiple the numerator by that number. So, 1 * 7 and 4 * 8. So you will have 7 and 32. This will show as 7/56 + 32/56. Finally, add the numerators - > 39/56
12 times 2 is 24, and 24 times 2 is 48, so there was 48 cookies
3x and 2x are alike terms, as they have the same variable
Answer:
A. 3(m-2) + 2(m-2) = 3m - 6 + 2m - 4
= 3m + 2m - 6 - 4
= 5m - 10
your welcome
Step-by-step explanation:
