All categories

3 years ago

5>r-3 I need help with this

2 answers:

4 0

Operations can be performed on this equation as if it said 5=r-3. So, simply add 3 to both sides and 3 will cancel out. The answer is 8>r.

kondaur [170]3 years ago

3 0

-15<r
that should be correct

You might be interested in

What are the steps for solving, 7,542÷3

valina [46]

Answer:

2514

Step-by-step explanation:

Do the long division and you'll find the answer.

8 0

2 years ago

What is the relationship between numbers

Kaylis [27]

What numbers? I need to know that to answer :/

5 0

3 years ago

Read 2 more answers

202 divided by 3 with a remaining number

svlad2 [7]

Answer:

$67 R \frac{1}{3}$

I hope this helps!

7 0

2 years ago

Read 2 more answers

For what value of x is sq 896z^15/225z^6 = xz^4/15

Ratling [72]

Answer:

Value of x is, 8

Step-by-step explanation:

Given: $\sqrt{\frac{896z^{15}}{225z^6}} =\frac{xz^4}{15} \sqrt{14z}$ ,.....[1]

To find the value of x:

Using exponent rules:

$(a^n)^m = a^{nm}$

$a^n \cdot a^m = a^{n+m}$

Taking square both sides in [1] we have;

$\frac{896z^{15}}{225z^6} = (\frac{xz^4}{15})^2 \cdot (14z)$

Simplify:

$\frac{896z^{15}}{225z^6} =\frac{x^2z^8}{225} \cdot (14z)$

$\frac{896z^{15}}{225z^6} =\frac{14x^2z^9}{225}$

Multiply both sides by $\frac{225}{14z^9}$ we get;

$x^2 = \frac{896 z^{15}}{225z^6} \times \frac{225}{14 z^9} = \frac{896 z^{15}}{14 z^{9+6}}$

Simplify:

$x^2 = \frac{896 z^{15}}{14 z^{15}} = 64$

$x = \sqrt{64}$

Simplify:

x = 8

Therefore, the value of x is, 8

5 0

2 years ago

In order for Brady to earn a B in his biology course, his test scores must average at least 80%. On the first 5 tests, he has an

larisa [96]

Hey there! I'm happy to help!

There were 5 tests needed to make an average of 77. These numbers have to add up to 385 (77×5) because that is what you divide by 5 to find the average which is 77.

Now, we want to find an average of 80 with 6 numbers. We multiply 80 and 6, showing us that the sum of these 6 numbers must be 480. Since 5 of these numbers are the same as with the 77 average, we know that one test score (the one Brady needs to get) is added to 385 to give us 480.

480-385=95

Therefore, Brady needs to earn a 95% on the last test to receive a B in the class.

8 0

3 years ago