The first one. The sum of all angles on a triangle is always equal to 180
Answer:
67.20$
Step-by-step explanation:
multiply 56 by 1.2
Our aim is to calculate the Radius so that to use the formula related to the area of a segment of a circle, that is: Aire of segment = Ф.R²/2
Let o be the center of the circle, AB the chord of 8 in subtending the arc f120°
Let OH be the altitude of triangle AOB. We know that a chord perpendicular to a radius bisects the chord in the middle. Hence AH = HB = 4 in
The triangle HOB is a semi equilateral triangle, so OH (facing 30°)=1/2 R. Now Pythagoras: OB² = OH² + 4²==> R² = (R/2)² + 16
R² = R²/4 +16. Solve for R ==> R =8/√3
OB² = OH² +
It would be 282.7 or 283 for the total surface area. Since the radius is three and the height is 12.
That would be B because 65 < 40 + 30
