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zhannawk [14.2K]
4 years ago
7

What is the equation of the axis of symmetry for the parabola y= 1/4(x+2)^2-7

Mathematics
1 answer:
Nezavi [6.7K]4 years ago
7 0
Your answer is -2 as the axis of symmetry is at -b/2a. So if you were to expand the equation, you would get y= x^2/4 +x -6 where b is 1 and 2a is ½ . Therefore -1 / ½ gives you -2
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-4(2+8)=(-4xN)= Show your answers
Elanso [62]

Answer:

n=10

Step-by-step explanation:

- 4(2 + 8) = ( - 4 \times n) \\  \frac{ - 4(10)}{ - 4}  =  \frac{ - 4n}{ - 4}  \\ 10 = n

5 0
3 years ago
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What are the partial products for 43 x 17
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4 0
3 years ago
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tresset_1 [31]
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8 0
4 years ago
What is the answer to (−2)³
svetlana [45]

(−2)³ = (-2)(-2)(-2)

Note that:

two negative numbers multiplied together results in a positive

one negative and one positive number multiplied results in a negative

Multiply:

(-2)(-2) = 4

4(-2) = -8

-8 is your answer

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4 0
4 years ago
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An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the
DedPeter [7]

<em><u>The inequality can be used to find the interval of time taken by the object to reach the height  greater than 300 feet above the ground is:</u></em>

d = -16t^2 + 1000

<em><u>Solution:</u></em>

<em><u>The object falls, its distance, d, above the ground after t seconds, is given by the  formula:</u></em>

d = -16t^2 + 1000

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

-16t^2 + 1000 > 300

Solve the inequality

Subtract 1000 from both sides

-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700

16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61

Time cannot be negative

Therefore,

t < 6.61

And the inequality used  is: -16t^2 + 1000>300

6 0
3 years ago
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