Question

Antawn Jamison is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 73%, percent of the time. What is the probability of Antawn Jamison making all of his next 9 free throw attempts?

Answer 1

It would be5.6% of the free throws

Answer 2

Answer: Probability of Antawn Jamison making all of his next 9 free throw attempts is 0.058 i.e. 5.8%

Step-by-step explanation:

Since we have given that

Probability that he will make his next one and he makes his free throws = 73%

Number of throws = 9

We will use "Binomial distribution":

$P(X=9)=^9C_9(0.73)^9(1-0.73)^{0}\\\\P(X=9)=1\times (0.73)^9(0.27)^0\\\\P(X=9)=0.058$

Hence, probability of Antawn Jamison making all of his next 9 free throw attempts is 0.058 i.e. 5.8%