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3 years ago

3B+4C=A b= what does B=

Mathematics

1 answer:

Oksana_A [137]3 years ago

5 0

Answer:

hdkd

Step-by-step explanation:

hsndbdjznx xjskd dnsksnd dust dnsjsnsnsjdbfnsbsjsbansjdbdbskensbsjsnsbzbzshbszb in conclusion need dndidndndndbd is the answer bc rnebdnrjdbdbdjebejr✨✨✨✨

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How do I solve proportions? Here’s my questions: 1. x/8=5/16 2. 5/12=15/x

Flura [38]

Proportions are very simple once you get the hang of them! What you do is cross multiple. :)

1. x/8=5/16

You first start by multiplying x and 16

Then multiply 5 and 8

So now you have 16x=40

Finally divide 16 from each side

You get: x+0.4!

2. 5/12=15/x

Remember to cross-multiply!

Now we have 5x=180

Next divide 5 from each side

You get: x=36!

7 0

3 years ago

What is this number in standard form? 5.75 x 10^9

sergey [27]

Step-by-step explanation:

57,500,000,000 is in standard form

5 0

3 years ago

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Select the curve generated by the parametric equations. Indicate with an arrow the direction in which the curve is traced as t i

bixtya [17]

Answer:

length of the curve = 8

Step-by-step explanation:

Given parametric equations are x = t + sin(t) and y = cos(t) and given interval is

−π ≤ t ≤ π

Given data the arrow the direction in which the curve is traces means

the length of the curve of the given parametric equations.

The formula of length of the curve is

$\int\limits^a_b {\sqrt{\frac{(dx}{dt}) ^{2}+(\frac{dy}{dt}) ^2 } } \, dx$

Given limits values are −π ≤ t ≤ π

x = t + sin(t) ...….. (1)

y = cos(t).......(2)

differentiating equation (1) with respective to 'x'

$\frac{dx}{dt} = 1+cost$

differentiating equation (2) with respective to 'y'

$\frac{dy}{dt} = -sint$

The length of curve is

$\int\limits^\pi_\pi {\sqrt{(1+cost)^{2}+(-sint)^2 } } \, dt$

$\int\limits^\pi_\pi \, {\sqrt{(1+cost)^{2}+2cost+(sint)^2 } } \, dt$

on simplification , we get

here using sin^2(t) +cos^2(t) =1 and after simplification , we get

$\int\limits^\pi_\pi \, {\sqrt{(2+2cost } } \, dt$

$\sqrt{2} \int\limits^\pi_\pi \, {\sqrt{(1+1cost } } \, dt$

again using formula, 1+cost = 2cos^2(t/2)

$\sqrt{2} \int\limits^\pi _\pi {\sqrt{2cos^2\frac{t}{2} } } \, dt$

Taking common $\sqrt{2}$ we get ,

$\sqrt{2}\sqrt{2} \int\limits^\pi _\pi ( {\sqrt{cos^2\frac{t}{2} } } \, dt$

$2(\int\limits^\pi _\pi {cos\frac{t}{2} } \, dt$

$2(\frac{sin(\frac{t}{2} }{\frac{t}{2} } )^{\pi } _{-\pi }$

length of curve = $4(sin(\frac{\pi }{2} )- sin(\frac{-\pi }{2} ))$

length of the curve is = 4(1+1) = 8

conclusion:-

The arrow of the direction or the length of curve = 8

7 0

3 years ago

Please help me I will give BRAINLIST

blsea [12.9K]

Answer: (0,29)

Good luck !

7 0

3 years ago

If your Gross Pay for a week at work is $340, and you have to pay 23% in taxes, what is your Net Pay (what you take home)?

Paladinen [302]

Answer:

$261.80 Net pay

Step-by-step explanation:

340 x 0.23 = $78.20 in taxes

$340 - $78.20 = $261.80 Net pay

7 0

3 years ago

Read 2 more answers