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lana [24]
3 years ago
7

A car traveling at 60 mph has how much more energy than a car going at 20 mph? K.E. increases by a factor of there is no increas

e in KE 3 times 9 times impossible to tell because the mass of the car is unknown
Biology
1 answer:
inn [45]3 years ago
6 0

Answer:

Assuming that the masses of the cars are the same

9 times

Explanation:

Kinetic energy can be computed using the formula:

KE = \dfrac{mv^{2}}{2}

Where:

KE = Kinetic energy

m = mass

v = velocity

As you can see in your problem, the velocity of the the first car mentioned is 3 times faster.

Looking at the the formula, velocity is raised to two (2). So if we put it in terms of equations this is how it will look:

Let v = velocity of the slower car

Car 1: velocity = (3v)

KE=\dfrac{mv^{2}}{2}

KE=\dfrac{(m)(3v)^{2}}{2}

KE=\dfrac{(m)9v^{2}}{2}

The increase is by a factor of 9.

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