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siniylev [52]
3 years ago
13

9z + 93 = -9z + 3 how do you solve for z?

Mathematics
1 answer:
Serhud [2]3 years ago
6 0

Answer:

z = -5

Step-by-step explanation:

add 9z to both side giving you ---> 18z+93 = 3

now subtract 93 from both sides ---> 18z = -90

now divide 18 by both sides and get your z

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which equation, written in standard form correctly represents this scenario and indicates what the variables represent?
pishuonlain [190]

The answer is the third option.

The explanation is shown below:

1. You must keep on mind the information given in the exercise:

- She bough 3 pounds of coffee.

- She bought 2 pounds of chocolate.

- She spent a total of $24.

2. Therefore, you can call the price per pound of coffee x and the price per pound of chocolate y.

3. When you multiply 3 pounds by the price per pound of coffee, you obtain the amount of money she spent for 3 pounds. When you multiply 2 pounds by the price per pound of chocolate, you obtain the amount of money she spent for 2 pounds. If you add both amounts, you obtain the total spent, which was $24.

4. Therefore, you can express this as following:

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4 years ago
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Answer:

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3 years ago
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Julli [10]

ANSWER

Center: (20,12)

Radius:23

EXPLANATION

The given circle has equation:

{x}^{2}  +  {y}^{2}  - 40x - 24y + 15 = 0

We complete the square as follows:

{x}^{2}  - 40x +  {y}^{2}  - 24y =  - 15

{x}^{2}  - 40x +   {( - 20)}^{2} +  {y}^{2}  - 24y +  {( - 12)}^{2}  =  - 15+   {( - 20)}^{2}+  {( - 12)}^{2}

{(x - 20)}^{2} +  {(y - 12)}^{2}  =  - 15+   400+  144

{(x - 20)}^{2} +  {(y - 12)}^{2}  = 529

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Comparing this equation to:

{(x - h)}^{2} +  {(y - k)}^{2}  =  {r}^{2}

We have

(h,k)=(20,12)

representing the center and

r = 23

being the radius.

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3 years ago
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NNADVOKAT [17]
\mathbb P(X=x)=\begin{cases}\dbinom3xp^x(1-p)^{3-x}&\text{for }0\le x\le3\\\\0&\text{otherwise}\end{cases}

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Answer:

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Step-by-step explanation:

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