Any rhombus has the same length for all for sides, so:
x + 14 = 3x +4
So, we get x = 5
Now, we can write
x + 14 = 8y
Since x = 5,
19 = 8y
so y = 19/8 = 2.375
<span>You can take any one of the equations and substitute the value of x or y in. The length is 19</span>
<span>r=2sin0-3cos0</span>
explain<span>using the formula that links Cartesian to Polar coordinates.<span>∙y=r<span>sinθ</span></span><span>∙x=r<span>cosθ</span></span>then : <span>r<span>sinθ</span>=3r<span>cosθ</span>+2</span>and <span>r<span>sinθ</span>−3r<span>cosθ</span>=2</span>hence <span>r<span>(<span>sinθ</span>−3<span>cosθ</span>)</span>=2</span></span>
<span>⇒r=<span><span>2<span><span>sinθ</span>−3<span>cosθ</span></span></span></span></span>
Function is p(x)=(x-4)^5(x^2-16)(x^2-5x+4)(x^3-64)
first factor into (x-r1)(x-r2)... form
p(x)=(x-4)^5(x-4)(x+4)(x-4)(x-1)(x-4)(x^2+4x+16)
group the like ones
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
multiplicity is how many times the root repeats in the function
for a root r₁, the root r₁ multiplicity 1 would be (x-r₁)^1, multility 2 would be (x-r₁)^2
so
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the root 1 and has multiplity 1
(x^2+4x+16) is not on the real plane, but the roots are -2+2i√3 and -2-2i√3, each multiplicity 1 (but don't count them because they aren't real
baseically
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the root 1 and has multiplity 1
Answer:
0.3
Step-by-step explanation:
