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NNADVOKAT [17]
4 years ago
13

for the following right triangle, find the side length x. round your answer to the nearest hundredth.​

Mathematics
2 answers:
zvonat [6]4 years ago
4 0
The answer is 7.14 , hope this helps!(:
lidiya [134]4 years ago
4 0

Answer:

7.14

Step-by-step explanation:

use Pythagorean theory

A squared + B squared = C squared

7 squared + X squared = 10 squared

49             + X squared = 100

                   X squared = 100 - 49

                   X squared = 51

                   X               =  7.14

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What soulution is true for x/3=1/4
andreyandreev [35.5K]

Answer:

x=3/4

Step-by-step explanation:

x/3=1/2^2

4x=3

4x/4=3/4

x=3/4

8 0
3 years ago
Please help me with this
Anni [7]
Sub in the numbers for x

6 0
3 years ago
A partition of a positive integer $n$ is any way of writing $n$ as a sum of one or more positive integers, in which we don't car
KATRIN_1 [288]
1*7 
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6 0
3 years ago
A company is moving large equipment in the boxes in the shape of cubes that holds 2000 ft.³ the company needs to move the boxes
In-s [12.5K]

Answer:

Step-by-step explanation:

Volume of a cube = L³

L is the length of the side of the cube;

Given

L = 2000ft³

Required

smallest whole foot length that could be used for the square platforms

Substitute the given into the formula to get the unknown length L

2000 = L³

Rearrange

L³ = 2000

Take cube root of both sides

∛L³ = ∛2000

L = ∛2000

L = 12.599

L≈ 12.6 feet

Hence the smallest whole foot length that could be used for the square platforms is 12.6feet

6 0
3 years ago
Help with number 6 please. thank you.​
Gwar [14]

Answer:

See Below.

Step-by-step explanation:

We are given that:

\displaystyle \frac{dT}{dt} = -k(T - T_0)

And we want to show that:

\displaystyle T = T_0+Ae^{-kt}

From the original equation, divide both sides by (<em>T</em> - <em>T₀</em>) and multiply both sides by dt. Hence:

\displaystyle \frac{dT}{T-T_0}= -k\, dt

Take the integral of both sides:

\displaystyle \int \frac{dT}{T- T_0} = \int -k \, dt

Integrate. For the left integral, we can use u-substitution. Note that <em>T₀</em> is simply a constant. Hence:

\displaystyle \ln\left|T - T_0\right| = -kt+C

Raise both sides to e:

\displaystyle e^{\ln\left|T-T_0\right|} = e^{-kt+C}

Simplify:

\displaystyle \begin{aligned} \left| T- T_0\right| &= e^{-kt} \cdot e^C \\ \\ &= e^C\left(e^{-kt}\right) \\ \\ &=Ae^{-kt} & \text{Let $e^C = A$}\end{aligned}

Since the temperature <em>T</em> will always be greater than or equal to the surrounding medium <em>T₀</em>, we can remove the absolute value. Hence:

<em />\left(T - T_0\right) = Ae^{-kt}<em />

Therefore:

\displaystyle T = T_0+Ae^{-kt}

5 0
3 years ago
Read 2 more answers
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