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MatroZZZ [7]
4 years ago
11

6. Which shape has a larger area: a rectangle that is 7 inches by inch, or a square with

Mathematics
1 answer:
RoseWind [281]4 years ago
5 0

Answer:

Rectangle = L x b = 7 x 7 = 49 inch^2

square = a^2 = 2^2=4 inch^2

Therefore the area of rectangle is more because it's area is greater than square

rectangle 's area > square's area.

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Give two ways to write the expression as a phrase.<br><br> $4w$
Assoli18 [71]

Answer: 4^1 or 4^1w

Step-by-step explanation:

There is 4 and one w therefore, you have 4^1 or, 4^1w

7 0
3 years ago
Suppose you bought this cone shaped hanging planter for a friend's birthday present. The planter measures 18 inches
WARRIOR [948]

Answer:

i bleve it is A

Step-by-step explanation:

let me know if im right.

3 0
3 years ago
Classify the number 38.93857982... with the correct rationale.
shtirl [24]

Answer:

38.93857982... is a irrational because it is a non-terminating, non-repeating decimal.

Step-by-step explanation:

Irrational number: the number which cannot be represented in the form of p/q where p and q are integer and q not equal to 0. In other words a Irrational number is a non terminating non repeating decimal number.

6 0
3 years ago
A plant is already 14 centimeters tall, and it will grow one centimeter every month.
Semenov [28]

Answer:

H=M+14

Step-by-step explanation:

When writing an equation you should always look at the problem and try to figure out what it is asking you to solve for. In this case you would be solving for the plants height (H). That will be one side of our equation.

<u>H=???</u>

Now we must think about how we would solve for the height. The plant grows 1 centimeter each month so we will put M on the other side. But since it is we will add 14 to that.

<u>H=M+14</u>

4 0
3 years ago
Use the procedures developed to find the general solution of the differential equation. (Let x be the independent variable.)
makkiz [27]

Solution :

Given :

2y''' + 15y'' + 24y' + 11y= 0

Let x = independent variable

(a_0D^n + a_1D^{n-1}+a_2D^{n-2} + ....+ a_n) y) =  Q(x)  is a differential equation.

If Q(x) \neq 0

It is non homogeneous then,

The general solution  = complementary solution + particular integral

If Q(x) = 0

It is called the homogeneous then the general solution =  complementary solution.

2y''' + 15y'' + 24y' + 11y= 0

$(2D^3+15D^2+24D+11)y=0$

Auxiliary equation,

$2m^3+15m^2+24m +11 = 0$

-1  | 2    15    24     11

   <u> | 0   -2    - 13    -11  </u>

      2    13    11       0

∴ 2m^2+13m+11=0

The roots are

$=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\frac{-13\pm \sqrt{13^2-4(11)(2)}}{2(2)}$

$=\frac{-13\pm9}{4}$

$=-5.5, -1$

So, m_1, m_2, m_3 = -1, -1, -5.5

Then the general solution is :

$= (c_1+c_2 x)e^{-x} + c_3 \ e^{-5.5x}$

 

8 0
3 years ago
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