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3 years ago

Evaluate the following expressions for x = -4

Mathematics

1 answer:

Vilka [71]3 years ago

6 0

Answer:

-1/16

-1/4

-4

Step-by-step explanation:

Put x as -4 and solve.

-4^-2 = 1/-4^2 = -1/16

-4^-1 = 1/-4 = -1/4

-4^0 = 1

-4^1 = -4

-4^2 = 16

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Find the equation of a line passing through (-4,-3) and perpendicular to<br> 3 x + 2 y = 14.

Reil [10]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$3x+2y=14\implies 2y=-3x+14\implies y=\cfrac{-3x+14}{2}\implies y = \cfrac{-3x}{2}+\cfrac{14}{2} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{3}{2}}x+7\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so therefore

$\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-3}{2}} ~\hfill \stackrel{reciprocal}{\cfrac{2}{-3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{2}{-3}\implies \cfrac{2}{3}}}$

so we're really looking for the equation of a line whose slope is 2/3 and passes through (-4 , -3)

$(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{\cfrac{2}{3}}(x-\stackrel{x_1}{(-4)}) \implies y+3=\cfrac{2}{3}(x+4) \\\\\\ y+3=\cfrac{2}{3}x+\cfrac{8}{3}\implies y=\cfrac{2}{3}x+\cfrac{8}{3}-3\implies y=\cfrac{2}{3}x-\cfrac{1}{3}$

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1 year ago

How do you get 0.1 x 2.4

adoni [48]

Answer:

the answer is .24

Step-by-step explanation:

when you multiply 0.1 x 2.4 it equals out to .24

0.1 x 2.4= .24

5 0

2 years ago

What is the slope of the line through (-2,-6) and (2, 2)?

Fofino [41]

The answer is B just did that question

6 0

3 years ago

triangle qrs has the angle measures shown. m∠q = (1x)° m∠r = (3x)° m∠s = (6x)° the measure of the obtuse angle equals

skelet666 [1.2K]

The sum of all interior angles in a triangle is 180°.

m∠q + m∠r + m∠s = 180°
1x + 3x + 6x = 180
10x = 180
x = 180/10
x = 18

m∠q = (1x)° = 1 x 18 = 18°
m∠ r = (3x)° = 3 x 18 = 54°
m∠s = (6x)° = 6 x 18 = 108°

m∠s is the obtuse angle because its measure is more than 90°. Its angle measures 108°

7 0

3 years ago

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Find the coordinates of the intersection of the diagonals of the parallelogram with the vertices W(−2, 5), X(2, 5), Y(4, 0),

emmasim [6.3K]

Using the midpoint formula, the coordinates of the intersection of the diagonals of the parallelogram is: (1, 2.5).

<h3>What are Diagonals of a Parallelogram?</h3>

The diagonals of a parallelogram bisect each other, therefore, the coordinates of their intersection can be determined using the midpoint formula, which is: $M(\frac{x_2 + x_1}{2}, \frac{y_2 + y_1}{2})$ .

A diagonal is XZ.

X(2, 5) = (x1, y1)

Z(0, 0) = (x2, y2)

Plug in the values

$M(\frac{0 + 2}{2}, \frac{0 + 5}{2})$

= (1, 2.5).

Learn more about the diagonals of a parallelogram on:

brainly.com/question/12167853

#SPJ1

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1 year ago