Question

A 9.5 V battery supplies a 2.5 mA current to a circuit for 7.0 h . Part A How much charge has been transferred from the negative to the positive terminal? Express your answer with the appropriate units. Δq Δ q = nothing nothing SubmitRequest Answer Part B How much electric potential energy has been gained by the charges that passed through the battery? Express your answer with the appropriate units. ΔU Δ U = nothing nothing SubmitRequest Answer Provide Feedback Next

Answer 1

Answer:

A)Δq = 63 C

B)ΔU=595.5 J

Explanation:

Given that

V = 9.5 V

I = 2.5 mA

t= 7 h

A)

We know that

Charge = current X time

q= I X t

$q=2.5\times 10^{-3}\times 7\times 60\times 60\ C$

q= 63 C

Δq = 63 C

B)

So the change in electric potential energy = I .V.t

Now by putting the values

$Electric\ potential\ energy\ =2.5\times 10^{-3}\times 9.5\times 7\times 60\times 60\ J$

Electric potential energy=595.5 J

ΔU=595.5 J